如何在OpenLayers中向向量添加彈出框？

Question

在我的程序的先前版本中，我使用markers來標記地圖上的點。 在當前版本中，我不得不從markers更改為vectors ，因為我需要額外的靈活性。 在標記解決方案中，我使用下面的函數向標記添加一個彈出框：

function createPopupBoxFeature(vector, lonLat, description) {
    var feature = new OpenLayers.Feature(vector, lonLat);

    feature.closeBox = true;
    feature.popupClass = OpenLayers.Class(OpenLayers.Popup.AnchoredBubble, 
        { "autoSize": true });
    feature.data.popupContentHTML = description;

    vector.events.register("mousedown", feature, function(evt) {
        if (this.popup == null) {
            this.popup = this.createPopup(this.closeBox);
            map.addPopup(this.popup);
            this.popup.show();
        } else {
            this.popup.toggle();
        }
        OpenLayers.Event.stop(evt);
    });

    return feature;
}

但它不再適用於vectors ，因為它們沒有events屬性。 我該如何解決？

Answer 1

實際上，官方的做法如下：

（注意：某些變量尚未在這些片段中聲明：longt，lat，map）

http://dev.openlayers.org/examples/light-basic.html

//Step 1 - create the vector layer
var vectorLayer = new OpenLayers.Layer.Vector("ExampleLayer",{
    eventListeners:{
        'featureselected':function(evt){
            var feature = evt.feature;
            var popup = new OpenLayers.Popup.FramedCloud("popup",
                OpenLayers.LonLat.fromString(feature.geometry.toShortString()),
                null,
                feature.attributes.message+"<br>"+feature.attributes.location,
                null,
                true,
                null
            );
            popup.autoSize = true;
            popup.maxSize = new OpenLayers.Size(400,800);
            popup.fixedRelativePosition = true;
            feature.popup = popup;
            map.addPopup(popup);
        },
        'featureunselected':function(evt){
            var feature = evt.feature;
            map.removePopup(feature.popup);
            feature.popup.destroy();
            feature.popup = null;
        }
    }
});

//Step 2 - add feature to layer
var p = new OpenLayers.Geometry.Point(longt, lat);
var feature = new OpenLayers.Feature.Vector(
     p.transform(new OpenLayers.Projection("EPSG:4326"), map.getProjectionObject()),
     {message:'foo', location:'bar'},
     {externalGraphic: '../img/marker.png', graphicHeight: 21, graphicWidth: 16}
);
vectorLayer.addFeatures(feature);

//Step 3 - create the selectFeature control
var selector = new OpenLayers.Control.SelectFeature(vectorLayer,{
    hover:true,
    autoActivate:true
});

//Step 4 - add the layer and control to the map
map.addControl(selector);
map.addLayer(vectorLayer);

Answer 2

由我自己解決。 方法如下：

// Used to display the dialog popup
var selectControl;
var selectedFeature;

添加SelectFeature

    selectControl = new OpenLayers.Control.SelectFeature(vectorLayer,
    {
        onSelect: onFeatureSelect,
        onUnselect: onFeatureUnselect 
    });
    map.addControl(selectControl);
    selectControl.activate();

事件處理程序

function onPopupClose(evt) {
    selectControl.unselect(selectedFeature);
}
function onPopupFeatureSelect(feature) {
    selectedFeature = feature;
    popup = new OpenLayers.Popup.FramedCloud("chicken",
        feature.geometry.getBounds().getCenterLonLat(),
        null, feature.name, null, true, onPopupClose);
    popup.panMapIfOutOfView = true;
    popup.autoSize = true;
    feature.popup = popup;
    map.addPopup(popup);
}
function onPopupFeatureUnselect(feature) {
    map.removePopup(feature.popup);
    feature.popup.destroy();
    feature.popup = null;
}

將彈出窗口的內容存儲在矢量名稱中。 可能有更好的解決方案，但我不在乎。 向彈出窗口添加彈出窗口已經足夠困難了。

vector.name = "Your popup content";