JavaScript：使用“或”語句聲明VAR

Question

代碼是這樣的

var $page_products = $page_name == 'products-uninterruptible-power-supply.php' OR 'products-uninterruptible-power-supply-np2031.php';

我已經嘗試使用

var $page_products = $page_name == 'products-uninterruptible-power-supply.php' || 'products-uninterruptible-power-supply-np2031.php';

但它仍然無法正常工作。 提前致謝！

Answer 1

假設您打算聲明一個變量$page_products ，如果$page_name等於這兩個字符串中的任何一個，則將其設置為true，否則將設置為false：

var $page_products = $page_name == 'products-uninterruptible-power-supply.php'
           || $page_name == 'products-uninterruptible-power-supply-np2031.php';

編輯：我只是注意到兩個頁面名稱都以相同的四個詞開頭，因此與其比較每個字符串，它可能更適合您測試$page_name的值是否以這些詞開頭，例如：

var $page_products =
           $page_name.indexOf('products-uninterruptible-power-supply') === 0;

Answer 2

這應該工作

var $page_products = ($page_name == 'products-uninterruptible-power-supply.php' || $page_name == 'products-uninterruptible-power-supply-np2031.php');

Answer 3

如果要有條件地分配文件名，則需要三元運算符：

var $page_products = ($page_name == 'products-uninterruptible-power-supply.php') ?
    'products-uninterruptible-power-supply.php' : 
    'products-uninterruptible-power-supply-np2031.php';