[英]How to calculate work hours per project per employee
我有一個PHP表單,將empID,projectNumber和Clock-in / Cout時間戳輸入到MySQL表中,如下所示:
沒有聲譽,我無法發布圖片,因此請在此處查看: 屏幕快照http://mailed.in/timecard/ss1.jpg
在生成如下所示的報告時,我需要幫助: 屏幕快照http://mailed.in/timecard/ss2.jpg
我可以完全在MySQL中執行此操作嗎? 怎么樣?
這可以幫助您:
SELECT
empID AS EmpID,
projectNumber AS ProjectNumber,
DATE(clocktime) AS StartDate,
TIMEDIFF(
(SELECT max(clocktime) from tableName where DATE( `clocktime` ) = CURDATE( )),
(SELECT min(clocktime) from tableName where DATE( `clocktime` ) = CURDATE( ))
) AS WorkHours
FROM `tableName`
WHERE
DATE( `clocktime` ) = CURDATE( )
GROUP BY empID
試試這個查詢-
CREATE TABLE table_proj (
empid INT(11) DEFAULT NULL,
projectnumber INT(11) DEFAULT NULL,
clocktime DATETIME DEFAULT NULL
);
INSERT INTO table_proj VALUES
(1, 1, '2011-09-27 10:02:22'),
(1, 1, '2011-09-27 11:17:32'),
(2, 2, '2011-09-27 11:34:13'),
(3, 3, '2011-09-27 11:01:21'),
(3, 3, '2011-09-27 13:36:28'),
(2, 2, '2011-09-27 13:55:39'),
(4, 4, '2011-09-27 14:25:07');
SELECT
empid, projectnumber, MIN(clocktime) startdate, TIMEDIFF(MAX(clocktime), MIN(clocktime)) workhours
FROM
table_proj
GROUP BY
empid, projectnumber
HAVING
COUNT(*) = 2;
+-------+---------------+---------------------+-----------+
| empid | projectnumber | startdate | workhours |
+-------+---------------+---------------------+-----------+
| 1 | 1 | 2011-09-27 10:02:22 | 01:15:10 |
| 2 | 2 | 2011-09-27 11:34:13 | 02:21:26 |
| 3 | 3 | 2011-09-27 11:01:21 | 02:35:07 |
+-------+---------------+---------------------+-----------+
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