PHP-比較兩個MySQL表

Question

是否有PHP代碼可讓您將2個MySQL表彼此進行比較，並將缺失的條目添加到其中？

我有兩張桌子。 hs_hr_employee和權利。 我想從hs_hr_employee表中的某些列中添加數據，以便它們在權限表中是相同的。

hs_hr_employee有多行，而權限表有5行。 權限表從hs_hr_employee表的emp_number，employee_id，emp_firstname，emp_lastname的4列中獲取信息

下面是代碼：

    <?php

$connection = mysql_connect('localhost','admin','root');

if( isset($_POST['submit']) )
{
    if( isset( $_POST['cb_change'] ) && is_array( $_POST['cb_change'] ))
    {
        foreach( $_POST['cb_change']  as $emp_number => $permission)
        {
            $sql = "UPDATE `rights` SET Permission='".mysql_real_escape_string($permission)."' WHERE emp_number='".mysql_real_escape_string($emp_number)."'";
            echo __LINE__.": sql: {$sql}\n";
            mysql_query( $sql );
        }
    }
}
?>
<p style="text-align: center;">
    <span style="font-size:36px;"><strong><span style="font-family: trebuchet ms,helvetica,sans-serif;"><span style="color: rgb(0, 128, 128);">File Database - Administration Panel</span></span></strong></span></p>
<p style="text-align: center;">
    &nbsp;</p>

<head>
<style type="text/css">
table, td, th
{
border:1px solid #666;
font-style:Calibri;
}
th
{
background-color:#666;
color:white;
font-style:Calibri;
}
</style>
</head>

    <form method="post" action="admin.php">

    <?php 


        if (!$connection)
          {
          die('Could not connect: ' . mysql_error());
          }

        mysql_select_db('users', $connection);

        //mysql_query('INSERT into rights(Emp_num, ID, Name, Surname) SELECT emp_number, employee_id, emp_firstname, emp_lastname FROM hs_hr_employee');


        $result = mysql_query("SELECT emp_number, employee_id, emp_firstname, emp_lastname, Permissions FROM rights");

        mysql_query("INSERT INTO rights (emp_number, employee_id, emp_firstname, emp_lastname)
                    SELECT emp_number, employee_id, emp_firstname, emp_lastname
                    FROM hs_hr_employee
                    ON DUPLICATE KEY UPDATE employee_id = VALUES(employee_id), emp_number = VALUES(emp_number)
                    ");

        echo "<center>";

        echo "<table >
        <tr>
        <th>Employee Number</th>
        <th>ID</th>
        <th>Name</th>
        <th>Surname</th>
        <th>Permissions</th>
        <th>Change</th>
        </tr>";

        while($row = mysql_fetch_array($result))
          {
          echo "<tr>";
          echo "<td>" . $row['emp_number'] . "</td>";
          echo "<td>" . $row['employee_id'] . "</td>";
          echo "<td>" . $row['emp_firstname'] . "</td>";
          echo "<td>" . $row['emp_lastname'] . "</td>";
          echo "<td>" . $row['Permissions'] . "</td>";
          echo "<td> <select name='cb_change[]'><option value='all'>All</option> <option value='remote'>Remote Gaming</option> <option value='landbased'>Landbased Gaming</option> <option value='general'>General Gaming</option> </select> </td>"; 
          echo "</tr>" ;
          }


          #echo "<td>" . $row['Change'] . "</td>";


          echo "</table>";

          echo "</center>";


        #$_POST['cb_permissions'];


     mysql_close($connection);


    ?>

<p style="text-align: center;">
    &nbsp;</p>
<p style="text-align: center;">
    &nbsp;</p>

<p style="text-align: right;">
    <input name="Save_Btn" type="button" value="Save" />


    </p>


</form>

知道怎么做嗎？

謝謝，布萊恩

Answer 1

我將在這里使用INSERT INTO SELECT 。

假設您通過社會安全號（ssn）識別了一名員工，並且使用此值來更新例如姓名和出生年月：

mysql_query("
INSERT INTO hs_hr_employee (ssn, name, birthyear)
SELECT ssn, name, birthyear
FROM hs_hr_rights
ON DUPLICATE KEY UPDATE name = VALUES(name), birthyear = VALUES(birthyear)
");

您還可以在FROM和ON DUPLICATE之間添加WHERE 。 像這樣：

...
FROM hs_hr_rights
WHERE birthyear IS NULL
ON DUPLICATE KEY UPDATE name = VALUES(name), birthyear = VALUES(birthyear)
...

雖然，我看不到需要復制值，因為在大多數情況下，您可以通過JOIN獲取它們。

Answer 2

select * from table a where a.common not in (select b.common from table b where a.common = b.common)

並同時運行

select * from table b where b.common not in (select a.common from table a where a.common = b.common)

在PHP中不可能，但是在MySQL中它的ans如上所述

PHP-比較兩個MySQL表

問題描述

2 個解決方案

解決方案1
3 已采納 2011-09-27 06:58:53

解決方案2
2 2011-09-27 07:01:28

PHP-比較兩個MySQL表

問題描述

2 個解決方案

解決方案1 3 已采納 2011-09-27 06:58:53

解決方案2 2 2011-09-27 07:01:28

解決方案1
3 已采納 2011-09-27 06:58:53

解決方案2
2 2011-09-27 07:01:28