JSON對象的Java表示

Question

我正在嘗試反序列化以下字符串，對於Java來說我是新手，我無法在我的一生中使用它...我現在僅嘗試在對象中解碼兩個字符串。 我的JSON和Java類如下。 我得到的結果變量確定。

{
   "result": "true",
   "recentlyMarkedTerritories": {
      "0": {
         "pk_activity": "471",
         "fk_activity_type": "100",
         "activity_content": "Hhhhh",
         "fk_user": "2",
         "activity_image": "2_QZe73f4t8s3R1317230457.jpg",
         "created": "1317244857",
         "activity_status": "1",
         "activity_location_lat": "43.515283",
         "activity_location_lon": "-79.880678",
         "fk_walk": null,
         "fk_event_location": "73",
         "user_point": "0",
         "public_image": "0",
         "fk_event_location_lat": "43.515273",
         "fk_event_location_lon": "-79.879989",
         "profile_image": "2_y9JlkI3CZDml1312492743.jpg",
         "user_gender": "1",
         "user_dob": "236073600",
         "user_nickname": "junoman",
         "isFriend": "false",
         "profile_image_thumb": "2_y9JlkI3CZDml1312492743_t.jpg",
         "activity_image_thumb": "2_QZe73f4t8s3R1317230457_t.jpg",
         "relationship_status_idx": "2",
         "isBlocked": "false"
      },
      "1": {
         "pk_activity": "469",
         "fk_activity_type": "100",
         "activity_content": "Jsjsjs",
         "fk_user": "1",
         "activity_image": null,
         "created": "1317244508",
         "activity_status": "1",
         "activity_location_lat": "43.515283",
         "activity_location_lon": "-79.880678",
         "fk_walk": null,
         "fk_event_location": "73",
         "user_point": "0",
         "public_image": "0",
         "fk_event_location_lat": "43.515273",
         "fk_event_location_lon": "-79.879989",
         "profile_image": "1_4Cpkofueqnrb1316895161.jpg",
         "user_gender": "1",
         "user_dob": "116841600",
         "user_nickname": "JoePennington",
         "isFriend": "false",
         "profile_image_thumb": "1_4Cpkofueqnrb1316895161_t.jpg",
         "activity_image_thumb": null,
         "relationship_status_idx": "1",
         "isBlocked": "false"
      },
      .....
   }
}

還有我下面的java類

RecentActivity infoList = null;
Gson gson = new Gson();
infoList = gson.fromJson(JSONString, RecentActivity.class);

public class RecentActivity {
    String result;
    recentlyMarkedTerritories recentlyMarkedTerritories = null;

    public RecentActivity() {

    }

    public class recentlyMarkedTerritories {
        public Set<recentlyMarkedTerritories> pk_activity = new HashSet<recentlyMarkedTerritories>() ;

        public recentlyMarkedTerritories() {    }
    }
}

請原諒我缺乏描述，但我確信代碼會有所幫助。 JSON已在其他應用程序中使用，因此不可更改。

謝謝！

Answer 1

這是一些不錯的JSON教程，可以幫助您。

GSON

JSON格式

帶有源代碼的JSON示例

更新

這樣嘗試

 try {
            JSONObject object = new JSONObject(jsonString);
            JSONObject myObject = object.getJSONObject("recentlyMarkedTerritories");

            for (int i = 0; i < object.length(); i++) {
                JSONObject myObject2 = myObject.getJSONObject(Integer.toString(i));
                System.out.println(myObject2.toString(2));  
            }
        } catch (Exception e) {
            e.printStackTrace();
        }

Answer 2

我不確定要寫的gson代碼，但json的結構看起來更像以下Java表示形式（盡管您可能需要布爾值和整數而不是字符串字段）：

public class RecentActivity {
    String result;
    Map<String,RecentlyMarkedTerritory> recentlyMarkedTerritories = null;
}

public class RecentlyMarkedTerritory {
    String pk_activity;
    // other fields
}