SQL多個共享WHERE條件

Question

我正在嘗試找到一個好的，有效的方式來運行這樣的查詢：

SELECT *
  FROM tableA a
 WHERE    a.manager IN (    SELECT id
                                 FROM tableB b
                           CONNECT BY PRIOR b.id = b.manager_id
                           START WITH b.id = 'managerBob')
       OR a.teamLead IN (    SELECT ID
                               FROM tableB b
                         CONNECT BY PRIOR b.ID = b.manager_id
                         START WITH b.ID = 'managerBob')
       OR a.creator IN (    SELECT id
                              FROM tableB b
                        CONNECT BY PRIOR b.id = b.manager_id
                        START WITH b.id = 'managerBob')

如您所見，我正在嘗試使用多個WHERE子句，但每個子句在等式的右側使用相同的數據集。 如果我使用多個子句，它似乎運行得非常慢，我很確定這是因為Oracle正在運行每個子查詢。 有沒有辦法讓這樣的工作？

SELECT *
  FROM tableA a
 WHERE    a.manager, 
          a.teamLead, 
          a.creator in (    SELECT id
                                 FROM tableB b
                           CONNECT BY PRIOR b.id = b.manager_id
                           START WITH b.id = 'managerBob')

順便說一句，我很抱歉，如果這是我可以用谷歌搜索的東西，我不知道該怎么稱呼它。

Answer 1

子查詢因子可能有所幫助：

WITH people AS
(    SELECT id
       FROM tableB b
    CONNECT BY PRIOR b.id = b.manager_id
      START WITH b.id = 'managerBob'
)
SELECT *
  FROM tableA a
 WHERE    a.manager IN (SELECT id FROM people)
       OR a.teamLead IN (SELECT id FROM people)
       OR a.creator IN (SELECT id FROM people)

Answer 2

你可以做：

WITH bob_subordinates AS (
(    SELECT id
       FROM tableB b
 CONNECT BY PRIOR b.id = b.manager_id
 START WITH b.id = 'managerBob')
SELECT * FROM tableA a
 WHERE a.manager in  (select id from bob_subordinates)
    OR a.teamlead in (select id from bob_subordinates)
    or a.creator  in (select id from bob_subordinates)

替代方案（檢查DISTINCT的使用：如果表B中的id不是唯一的，那么這不是等價的）：

WITH bob_subordinates AS (
(    SELECT DISTINCT id
       FROM tableB b
 CONNECT BY PRIOR b.id = b.manager_id
 START WITH b.id = 'managerBob')
SELECT DISTINCT a.*
  FROM tableA a JOIN bob_subordinates b ON b.id IN (a.manager, a.teamlead, a.creator);

Answer 3

根據評論更新 - 試試

SELECT A.* FROM 
(SELECT bb.id FROM tableB bb CONNECT BY PRIOR bb.id = bb.manager_id START WITH bb.id = 'managerBob') B INNER JOIN TABLEA A ON B.ID IN (A.MANAGER, A.TEAMLEAD, A.CREATOR)