如何在c ++的代碼中將printf語句限制為每行80個字符？

Question

我的教授要求我的代碼每行不超過80個字符，但我有一些超出此限制的printf語句。 有沒有辦法在不改變輸出的情況下將此語句分成兩行或多行？

請求示例：

printf("\n%-20s %-4d %-20s %-4d %-20s %-4d\n%-20s %-4d %-20s %-4d%-20s %-4d\n%-20s %-4d %-20s %-4d %-20s %-4d\n%-20s %-4d %-20s %-4d %-20s %-4d\n%-20s %-4d %-20s %-4d\n", "1 - Ones", ones, "2 - Twos", twos, "3 - Threes", threes, "4 - Fours", fours, "5 - Fives", fives, "6 - Sixes", sixes, "7 - Three of a Kind", threeOfAKind, "8 - Four of a Kind", fourOfAKind, "9 - Full House", fullHouse, "10 - Small Straight", smallStraight, "11 - Large Straight", largeStraight, "12 - Yahtzee", yahtzee, "13 - Chance", chance, "Total Score: ", score);

Answer 1

在C ++中，您可以像這樣破壞文字字符串：

printf("This is a very long line. It has two sentences.\n");

成

printf("This is a very long line. "
       "It has two sentences.\n");

在解析之前，編譯器將由空格分隔的任何雙引號字符串合並為一個字符串。 結果字符串不包含任何額外的字符，除了每對雙引號之間的內容（因此，沒有嵌入的換行符）。

對於帖子中包含的示例，我可能會執行以下操作：

printf("\n%-20s %-4d %-20s %-4d %-20s %-4d\n"
       "%-20s %-4d %-20s %-4d%-20s %-4d\n"
       "%-20s %-4d %-20s %-4d %-20s %-4d\n"
       "%-20s %-4d %-20s %-4d %-20s %-4d\n"
       "%-20s %-4d %-20s %-4d\n",
       "1 - Ones", ones, "2 - Twos", twos, "3 - Threes", threes,
       "4 - Fours", fours, "5 - Fives", fives, "6 - Sixes", sixes,
       "7 - Three of a Kind", threeOfAKind,
           "8 - Four of a Kind", fourOfAKind,
           "9 - Full House", fullHouse,
       "10 - Small Straight", smallStraight,
           "11 - Large Straight", largeStraight,
           "12 - Yahtzee", yahtzee,
       "13 - Chance", chance, "Total Score: ", score);