在JQuery，JavaScript中解析JSON響應時出錯

Question

我將其作為JSON響應進行跟蹤，但某些索引的空格類似“員工ID”。 這就是為什么我無法解析它。 誰能建議用JavaScript解析的方式？

{
    "Employees": [
        {
            "Employee": {
                "Employee ID": "777",
                "Short Name": "abc",
                "First name": null,
                "Middle name": null,
                "Last name": null,
                "Designation": "Senior Engineer",
                "Ext-1": null,
                "Ext-2": null,
                "Mobile-1": null,
                "Mobile-2": null,
                "Email": "a.b@gmail.com"
            }
        },
        {
            "Employee": {
                "Employee ID": "888",
                "Short Name": "xyz",
                "First name": null,
                "Middle name": null,
                "Last name": null,
                "Designation": "Test Lead",
                "Ext-1": null,
                "Ext-2": null,
                "Mobile-1": null,
                "Mobile-2": null,
                "Email": "c.d@gmail.com"
            }
        }
    ]
}

我的代碼-

 function GetContacts() {
    $.ajax({
        type: "GET",
        contentType: 'application/json; charset=utf-8',
        url: "http://. . . . . .",

        dataType: "json",
        success: function(data) {

            //alert(data.getString("Employee ID"));
            $.each(data, function(i, contactList) {

                alert('First Loop' + i);
                alert('First Loop' + contactList[0]);

                $.each(contactList, function(j, Contact) {
                    //alert('Second Loop'+Contact);
                    var fnalObj = Contact;
                    //alert(fnalObj);
                    //alert(fnalObj.["Employee"]["Employee ID"]);
                    //alert(Employees[j]["Employee"]["Email"]);
                    //alert(Employees[0]["Employee"]["Employee ID"]);
                    alert(fnalObj.Employee.Email);
                    alert(fnalObj.Employee.Designation);
                    alert(fnalObj.Employee.Ext - 1);
                    alert(fnalObj.Employee.Mobile - 1);
                });
            });
        },
        error: function(XMLHttpRequest, textStatus, errorThrown) {
            alert(errorThrown);
            alert(textStatus);
        }
    });
}

Answer 1

解析很好。

問題是訪問由非字母數字字符組成的鍵，例如空格，破折號等。

這些屬性必須使用[]符號處理，如下所示

alert(fnalObj.Employee['Employee ID']);
alert(fnalObj.Employee['Ext-1']);

演示在http://jsfiddle.net/h9sbn/

Answer 2

您不能執行fnalObj.Employee.Ext - 1 。 正確的方法是fnalObj.Employee['Ext-1'] 。 這是jsFiddle http://jsfiddle.net/naryad/VNXa5/1/

使用fnalObj.Employee.Ext - 1 ，它將解析為undefined - 1 ，這反過來又會返回NaN

同樣適用於fnalObj.Employee.Mobile - 1

Answer 3

$.each(contactList, function(j, Contact) {
    //alert('Second Loop'+Contact);
    var fnalObj = Contact;
    $.each(finalObj, function (key, value) {
        var newKey = key.replace(/[\s]\-/g, '_');
        delete finalObj[key];
        finalObj[newKey] = value;
    });
    //revised alerts here.
});