[英]Running Query inside WHILE/Loop
在這里需要幫助,得到一個查詢,該查詢計算每個成員的行數並將其通過電子郵件發送給他們。
因此,現在他們收到一封簡單的電子郵件,告訴他們有多少帖子,我已經找到了一種在主查詢中運行第二個查詢的方法(該方法會計算帖子表中的帖子,並根據其帳戶信息生成電子郵件另一個表)我們想要的是讓電子郵件也顯示每個帖子,我已經在第一個查詢中加入了表,但似乎找不到在while語句中運行第二個表的方法。
這是我們當前擁有的代碼。 任何幫助將不勝感激。
<?php
//Connect to mysql server
$link = mysql_connect(localhost, xxxxxxx, xxxxxxxx);
if(!$link) {
die('Failed to connect to server: ' . mysql_error());
}
//Select database
$db = mysql_select_db(systm_test);
if(!$db) {
die("Unable to select database");
}
$count = 0;
$date = date("Y-m-d", $_SERVER['REQUEST_TIME']);
$day = date("l F jS, Y", $_SERVER['REQUEST_TIME']);
$qry= sprintf("SELECT p.tech, p.date, e.email, e.fullname, "
. "COUNT( * ) AS record_count "
. "FROM users_test AS e "
. "JOIN sc AS p ON e.tech = p.tech "
. "WHERE DATE = '%s' "
. "GROUP BY p.tech, e.fullname, e.email, p.date",
$date
);
$result = mysql_query($qry);
if (!$result) {
# something went wrong...
error_log(sprintf('%d: %s', mysql_errno(), mysql_error()));
echo 'Unable to retrieve callpost report';
} else {
while ($node = mysql_fetch_object($result)) {
$headers = "From: xxxxxxxxxx <noreply@xxxxx.xxx>\r\n";
$headers .= "Content-Type: text/html; charset=\"iso-8859-1\"\r\n";
$headers .= "X-Priority: 1 (Higuest)\r\n";
$headers .= "Importance: High\r\n";
$subject = sprintf('%s | Post Report', $node->fullname);
$date = date("Y-m-d", $_SERVER['REQUEST_TIME']);
$body = sprintf(
'Dear %s, <br><br>
Your daily post report for %s.
<br>
<br>
System Info<br>
------------------------------------<br>
Member Id: <b>%d</b><br>
Posts: <b>%d</b>
<br>
System Name: TEST<br>',
$node->fullname,
$day,
$node->tech,
$node->record_count
);
if (!mail($node->email, $subject, $body, $headers))
{
error_log(
sprintf('failed sending email report to %s (%d)',
$node->fullname,
$node->tech)
);
}
} //end while statement
mail($node->email, $subject, $body, $headers);
}
}
?>
子選擇是您想要的。 就像是。
"SELECT p.tech, p.date, e.email, e.fullname, "
. "COUNT( * ) AS record_count, "
. "(SELECT COUNT(*) FROM Posts z WHERE z.author = e.tech) as post_count "
. "FROM users_test AS e "
. "JOIN sc AS p ON e.tech = p.tech "
. "WHERE DATE = '%s' "
. "GROUP BY p.tech, e.fullname, e.email, p.date"
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