[英]Oracle Triggers Update at Another Table
我正在嘗試在Oracle中創建觸發器。 我知道sql,但我從未創建過觸發器。 我有以下代碼:
create or replace trigger "PASSENGER_BOOKING_T1"
AFTER
insert on "PASSENGER_BOOKING"
for each row
begin
IF (:NEW.CLASS_TYPE == 'ECO')
SELECT F.AVL_SEATS_ECOCLASS,F.FLIGHT_ID INTO SEAT, FLIGHT_INFO
FROM BOOKING B, JOURNEY_FLIGHT J, FLIGHT F
WHERE B.JOURNEY_ID = J.JOURNEY_ID and F.FLIGHT_ID = J.FLIGHT_ID;
UPDATE FLIGHT
SET AVL_SEATS_ECOCLASS = (SEAT-1)
WHERE FLIGHT_ID = FLIGHT_INFO;
END IF;
end;
當Passenger_Booking表中有插入內容時,將觸發此觸發器。 座位數減少了一個(在不同的桌子上)。
選擇查詢應該沒問題,但是某處有問題。 有人可以建議什么嗎?
我將身體部位改為這個,但是仍然有問題:
UPDATE FLIGHT
SET AVL_SEATS_ECOCLASS =
(SELECT F.AVL_SEATS_ECOCLASS FROM BOOKING B, JOURNEY_FLIGHT J, FLIGHT F WHERE B.JOURNEY_ID = J.JOURNEY_ID and F.FLIGHT_ID = J.FLIGHT_ID;
);
IF
語句需要THEN
=
來測試是否相等,而不是==
當我做這三件事時,我會得到這樣的東西
create or replace trigger PASSENGER_BOOKING_T1
AFTER insert on PASSENGER_BOOKING
for each row
declare
l_seat flight.seat%type;
l_flight_id flight.flight_id%type;
begin
IF (:NEW.CLASS_TYPE = 'ECO')
THEN
SELECT F.AVL_SEATS_ECOCLASS,F.FLIGHT_ID
INTO l_seat, l_flight_id
FROM BOOKING B,
JOURNEY_FLIGHT J,
FLIGHT F
WHERE B.JOURNEY_ID = J.JOURNEY_ID
and F.FLIGHT_ID = J.FLIGHT_ID;
UPDATE FLIGHT
SET AVL_SEATS_ECOCLASS = (l_seat-1)
WHERE FLIGHT_ID = l_flight_id;
END IF;
end;
除了這些語法錯誤,如果SELECT INTO
語句正確,我會感到震驚。 SELECT INTO
必須恰好返回1行。 您的查詢幾乎肯定會返回多行,因為沒有謂詞會將查詢限制為特定的航班或特定的預訂。 大概您想加入PASSENGER_BOOKING
表中的一列或多列。
此外,如果這不是家庭作業,則請確保您了解這種觸發器在多用戶環境中無法正常工作。
只是一個瘋狂的猜測
編輯賈斯汀指出(感謝賈斯汀)平等檢查
create or replace trigger "PASSENGER_BOOKING_T1"
AFTER
insert on "PASSENGER_BOOKING"
for each row
declare
v_flight_id FLIGHT.FLIGHT_ID%TYPE;
begin
IF (:NEW.CLASS_TYPE = 'ECO') THEN
SELECT F.ID into v_flight_id
FROM BOOKING B, JOURNEY_FLIGHT J, FLIGHT F
WHERE B.ID = :NEW.BOOKING_ID -- note that I've made this up
AND B.JOURNEY_ID = J.JOURNEY_ID AND F.FLIGHT_ID = J.FLIGHT_ID;
UPDATE FLIGHT
SET AVL_SEATS_ECOCLASS = (SEAT-1)
WHERE ID = v_flight_id;
END IF;
end;
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