SQL查詢有什么問題？

Question

我該如何解決此SQL查詢？

$q = $db->sqlQuery("SELECT * FROM project WHERE email = " . $email . "");

Answer 1

$q = $db->sqlQuery("SELECT * FROM project WHERE email = '" . $email . "'");

Answer 2

$q = $db->sqlQuery("SELECT * FROM project WHERE email = '$email'");

Answer 3

您可以嘗試以下方法：

$q = $db->sqlQuery("SELECT * FROM project WHERE email = '" . $email . "'");

缺少單引號' ，因為它是一個字符串，所以應該將$email值括起來。

Answer 4

$q = $db->sqlQuery("SELECT * FROM project WHERE email = '" . $email . "'");

您需要對字符串變量使用''

錯誤： SELECT * FROM project WHERE email = email@email.email

確定： SELECT * FROM project WHERE email = 'email@email.email'

Answer 5

轉義參數。

$q = $db->sqlQuery("SELECT * FROM project WHERE email = '" . $email . "'");