[英]How do I get phone number from this JSON response?
有點幽默:書呆子總是有問題獲取電話號碼:(。
我正試圖從這個谷歌獲取電話號碼api響應,在iOS上開發應用程序。
{
"html_attributions" : [],
"result" : {
"address_components" : [
{
"long_name" : "48",
"short_name" : "48",
"types" : [ "street_number" ]
},
{
"long_name" : "Pirrama Road",
"short_name" : "Pirrama Road",
"types" : [ "route" ]
},
{
"long_name" : "Pyrmont",
"short_name" : "Pyrmont",
"types" : [ "locality", "political" ]
},
{
"long_name" : "NSW",
"short_name" : "NSW",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "AU",
"short_name" : "AU",
"types" : [ "country", "political" ]
},
{
"long_name" : "2009",
"short_name" : "2009",
"types" : [ "postal_code" ]
}
],
"formatted_address" : "5/48 Pirrama Road, Pyrmont NSW, Australia",
"formatted_phone_number" : "(02) 9374 4000",
"geometry" : {
"location" : {
"lat" : -33.8669710,
"lng" : 151.1958750
}
},
"icon" : "http://maps.gstatic.com/mapfiles/place_api/icons/generic_business-71.png",
"id" : "4f89212bf76dde31f092cfc14d7506555d85b5c7",
"international_phone_number" : "+61 2 9374 4000",
"name" : "Google Sydney",
"rating" : 4.60,
"reference" : "CnRlAAAAAfV6JIqSzL8Cf4VnXn0EaI1d5k3IPhdkEonq0MxiUbQFFSVuptVbXbNH4mrevb0bc7G8yWqTUv76i4KTuO_Wf3OrRHjCJJwzQ0mNLjbYGSVqy2eqyrgOUkl6S_sJfTbHzWZYrfPy7KZaet0mM5S6thIQJYuy5v_JD--ZxXEJLWTQRRoU5UaciXBBo89K-bce18Ii9RsEIws",
"types" : [ "store", "establishment" ],
"url" : "http://maps.google.com/maps/place?cid=10281119596374313554",
"vicinity" : "5/48 Pirrama Road, Pyrmont",
"website" : "http://www.google.com.au/"
},
"status" : "OK"
}
目標IS:“international_phone_number”:“+ 61 2 9374 4000”
我到目前為止的努力,
NSDictionary *results = [responseString JSONValue];
placeInfo = [results objectForKey:@"result"];
//Getting result details but than I am stuck how to get to that international phone number?
任何輸入將不勝感激! 謝謝
您具有上述轉儲中的結構。 最外層的結構是字典,一些字典條目包含數組,一些包含其他字典。 ( {}
表示字典, []
表示數組。)
所以你可以看到“結果”產生另一個字典。 該詞典的一個要素是“formatted_phone_number”。 它包含一個字符串形式的電話號碼。
剝洋蔥層。
嘗試:
NSString *phoneNumber = [placeInfo objectForKey:@"formatted_phone_number"];
NSLog(@"Her Phone Number: %@", phoneNumber);
placeInfo = [results objectForKey:@"result"];
NSString *internationalPhone = [placeInfo objectForKey:@"international_phone_number"];
試試這個,看看你做NSLog時電話號碼是否出現(@“phone:%@”,internationalPhone)
NSError *parseError = nil;
// Your test json as NSString
NSString * json = @"{ \"html_attributions\" : [], \"result\" : { \"address_components\" : [ { \"long_name\" : \"48\", \"short_name\" : \"48\", \"types\" : [ \"street_number\" ] }, { \"long_name\" : \"Pirrama Road\", \"short_name\" : \"Pirrama Road\", \"types\" : [ \"route\" ] }, { \"long_name\" : \"Pyrmont\", \"short_name\" : \"Pyrmont\", \"types\" : [ \"locality\", \"political\" ] }, { \"long_name\" : \"NSW\", \"short_name\" : \"NSW\", \"types\" : [ \"administrative_area_level_1\", \"political\" ] }, { \"long_name\" : \"AU\", \"short_name\" : \"AU\", \"types\" : [ \"country\", \"political\" ] }, { \"long_name\" : \"2009\", \"short_name\" : \"2009\", \"types\" : [ \"postal_code\" ] } ], \"formatted_address\" : \"5/48 Pirrama Road, Pyrmont NSW, Australia\", \"formatted_phone_number\" : \"(02) 9374 4000\", \"geometry\" : { \"location\" : { \"lat\" : -33.8669710, \"lng\" : 151.1958750 } }, \"icon\" : \"http://maps.gstatic.com/mapfiles/place_api/icons/generic_business-71.png\", \"id\" : \"4f89212bf76dde31f092cfc14d7506555d85b5c7\", \"international_phone_number\" : \"+61 2 9374 4000\", \"name\" : \"Google Sydney\", \"rating\" : 4.60, \"reference\" : \"CnRlAAAAAfV6JIqSzL8Cf4VnXn0EaI1d5k3IPhdkEonq0MxiUbQFFSVuptVbXbNH4mrevb0bc7G8yWqTUv76i4KTuO_Wf3OrRHjCJJwzQ0mNLjbYGSVqy2eqyrgOUkl6S_sJfTbHzWZYrfPy7KZaet0mM5S6thIQJYuy5v_JD--ZxXEJLWTQRRoU5UaciXBBo89K-bce18Ii9RsEIws\", \"types\" : [ \"store\", \"establishment\" ], \"url\" : \"http://maps.google.com/maps/place?cid=10281119596374313554\", \"vicinity\" : \"5/48 Pirrama Road, Pyrmont\", \"website\" : \"http://www.google.com.au/\" }, \"status\" : \"OK\" }";
// Converting to data and stripping last 0x0 byte
NSData* aweData = [json dataUsingEncoding:NSUTF8StringEncoding];
[aweData subdataWithRange:NSMakeRange(0, [aweData length] - 1)];
id jsonObject = [NSJSONSerialization JSONObjectWithData:aweData options:NSJSONReadingAllowFragments error:&parseError];
NSString* result = [[jsonObject objectForKey:@"result"] objectForKey:@"international_phone_number"]; // +61 2 9374 4000
您還可以通過使用避免創建額外變量
NSString* phoneNumber = [results objectForKeyPath@"result.international_phone_number"];
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