fastcsv輸出錯誤？ Ruby中的太多

Question

我正在Ruby中實現，我只想讀取CSV文件。 我的CSV看起來像：

"official_code","username","lastname","firstname","email","Course Groups","password"
"1626","000078sr","LENS","Ser","blab@hogent.be","project1g43","pwd7975"
"7334","000116jd","DE ","Joen","je0116@.hogent.be","project1g08","pwd5259"
"2003","000136bv","VACKE","Bert","hogent.be","project1g18","pwd5908"
"4065","000166cr","ROHøJ","Chrian","chrhogent.be","project1g10","pwd5000"

它由Excel制成，並設置為CSV文件

但是當我在應用程序中執行以下操作時：

 FasterCSV.foreach(file.path, {:headers=>true }) do |row|

            @samples[i] = row
      i += 1
    end # do

 if @samples.size > 0
      @headers = @samples[0].headers
    end 

在我看來，我只是這樣做：

<%= @headers.inspect %>


<ul>
<% @samples.each do |a| %>
<li>
<%= a %>
</li>
<% end %>
</ul>

我得到：

["\"official_code\",\"username\",\"lastname\",\"firstname\",\"email\",\"Course Groups\",\"password\""]

"""1626"",""000078sr"",""ENS"",""Sder"",""san.hogent.be"",""project1g43"",""pwd7975"""
"""7334"",""000116jd"",""DE VOS"",""Jen"",""jeroen.ogent.be"",""project1g08"",""pwd5259"""
"""2003"",""000136bv"",""VYCKE"",""Bet"",""berent.hogent.be"",""project1g18"",""pwd5908"""
"""4065"",""000166cr"",""ROøJ"",""Chstian"",""chr.hogent.be"",""project1g10"",""pwd5000"""

因此，有很多方法可以實現。有人知道我在做什么錯嗎？就像行只有1列。如果我做samples[0].each我只有1項。整行而不是列。

Answer 1

當您引用@samples您正在查看的是一個行數組，每個行都是一個解析字段的數組。

因此，當您使用@samples.each do |a| ， a是一行，我認為您正在該行上調用#inspect的結果。

如果嘗試這樣的話會怎樣？

options = { :headers=>true, :return_headers => true }
@samples = FasterCSV.read(file.path, options).to_a

if @samples.size > 0
  @headers = @samples.shift 
end 

如果要獲取實際標簽，則需要:return_headers=>true ； :headers=>true僅告訴FasterCSV有標題-默認情況下將其丟棄。 FasterCSV.read獲取並解析所有數據，這比自己構建數組更簡單。 請注意最后的to_a ，它迫使結果實際上是一個數組-可能會使下一部分變得更簡單。

如果您按如下方式修改視圖（在標題上使用#join而不是#inspect並#join上添加#join ）會發生什么？

<%= @headers.join(', ') %>

<ul>
<% @samples.each do |a| %>
<li>
<%= a.join(', ') %>
</li>
<% end %>
</ul>

如果那不能解決問題，希望您至少應該進一步了解正在發生的事情...