[英]Condition within GROUP_CONCAT()
伙計我的數據庫中有以下表格
地點
項目
里程碑
狀態
project_milestones
在這里,為了列出所有項目的所有里程碑(其狀態為9),我正在使用以下查詢
SELECT projects.projectname, locations.name, DATE_FORMAT(projects.created_at, '%d-%m-%y') as projectdate,
GROUP_CONCAT(milestones.name ORDER BY project_milestones.milestone_id ASC separator '<br/>') AS milestones
FROM projects INNER JOIN locations ON projects.location_id=locations.id
INNER JOIN project_milestones ON project_milestones.project_id=projects.id AND project_milestones.status_id=9
INNER JOIN milestones ON project_milestones.milestone_id=milestones.id
INNER JOIN statuses ON project_milestones.status_id=statuses.id
AND project_milestones.milestone_id=milestones.id GROUP BY projects.projectname
結果如下所示
Location Date Created Project Name Milestones (Status 9) Bangalore 25-10-11 ABCD CSO Contacts, Developer Bangalore 11-11-11 Friday Establish, Publish list Bangalore 08-11-11 XX CSO Contacts, Assemble,Layouts
它工作得很好,但我需要的是另一個GROUP_CONCAT專欄列出里程碑(狀態10)來顯示所有項目的所有里程碑(狀態為10)。
輸出與列出[Status-9里程碑]和[狀態-10里程碑]的所有項目一樣。 我怎樣才能做到這一點?
SELECT *,
(
SELECT GROUP_CONCAT(m.name ORDER BY m.id)
FROM project_milestones pm
JOIN milestones m
ON m.id = pm.milestone_id
WHERE pm.project_id = p.id
AND pm.status_id = 9
) milestone_9,
(
SELECT GROUP_CONCAT(m.name ORDER BY m.id)
FROM project_milestones pm
JOIN milestones m
ON m.id = pm.milestone_id
WHERE pm.project_id = p.id
AND pm.status_id = 10
) milestone_10
FROM projects p
JOIN locations l
ON l.id = p.location_id
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