[英]PHP code inside javascript
我不知道javascript的工作原理,但是我能夠通過從不同站點進行復制來編寫以下代碼。
我的目標是要有2個單選框(1 =印度,2 =印度以外的其他國家),如果選擇“印度以外的其他國家”,則會顯示一個下拉框,其中顯示了所有國家/地區的名稱。
從數據庫中選擇下拉菜單,並通過自定義php函數實現。
我可以根據我的單選框選擇使代碼顯示下拉列表。
我無法做的事情如下:
這是表格的代碼:
<form action="<?php $_SERVER['PHP_SELF']?>" method="post">
<fieldset>
<br />
<script type="text/javascript">
function onclickradio(entry){
if (entry === true) {
alert("YOU HAVE CHOSEN INDIA");
}
else {
document.getElementById('OTHER THAN INDIA').innerHTML = '</br><?php dropdown('country');?>';
}
}
</script>
Country: </br>
<input onclick="onclickradio(document.getElementById('INDIA').checked);" id="INDIA" name="country" type="radio" checked="checked"/> INDIA
<input onclick="onclickradio(document.getElementById('INDIA').checked);" id="OTHER THAN INDIA" name="country" type="radio"/> OTHER THAN INDIA
<br /><br /><br />
State: <input type="text" name="State" maxlength="30"/><br />
Line1: <input type="text" name="Line1" maxlength="50" /><br />
Line2: <input type="text" name="Line2" maxlength="50" /><br />
City: <input type="text" name="City" maxlength="40" /><br />
PIN Code: <input type="text" name="PIN_Code" maxlength="8" /><br />
<input type="submit" name="submit_address" value="Submit Address" />
</fieldset>
</form>
這是自定義PHP下拉功能的代碼:
<?php
function dropdown($tablename) /*remember to add single quote around the input*/
{
$sql="SELECT * FROM ".$tablename;
$result=mysqli_query($GLOBALS["connection"], $sql)
or die('Error in running SELECT query');
$options=""; //initialising the variable, so that it can be concatenated later
while ($row=mysqli_fetch_array($result))
{
$x=0; /*$x is the index of the field in a row (it has to start with $x=0;
because the first index is 0 in php*/
$rowstr=" # "; /*initialising the variable,
so that it can be concatenated later*/
while ($x+1<=mysqli_num_fields($result)) /*mysqli_num_fields gives the actual number of fields, and not the index.
Since the index starts with 0, it is to be incremented by 1
before comparison with the mysqli_num_fields*/
{
$rowstr.= $row[$x]." # "; //concatenation operator
$x=$x+1;
}
$options.="<option value=".$rowstr.">".$rowstr."</option>"; //concatenation operator
}
Echo "<select>".$options."</select>";
}
?>
我想到了幾件事:
元素的ID字段不能有空格。 只需嘗試刪除"OTHER THAN INDIA"
空格或替換為OTHER_THAN_INDIA
如果選擇了印度,則清除選擇
function onclickradio(entry) {
if(entry===true) {
alert("YOU HAVE CHOSEN INDIA");
document.getElementById('OTHER THAN INDIA').innerHTML = '';
}
else {
document.getElementById('OTHER THAN INDIA').innerHTML = '<br/><?php dropdown('country');?>';
}
}
嘗試這個:
$(document).ready(function() {
// hide address inputs
$('#address').hide();
// show address inputs if the not india button is pressed
$('#not-india').click(function() {
$('#address').show();
});
// re-hide address inputs if india is selected
$('#india').click(function() {
$('#address').hide();
});
});
您還必須在頁面中包含jQuery。
小提琴: http : //jsfiddle.net/EN4jB/6/
請注意,我使用了以下標記-特別要注意的是此div的ID。
<input id="india" name="country" type="radio" checked="checked"/> India
<input id="not-india" name="country" type="radio" /> Not India
<br />
<div id="address">
<p><select>
<option>USA</option>
<option>UK</option>
<option>Ireland</option>
<option>etc...</option>
</select>
</p>
<p>State: <input type="text" name="State" maxlength="30"/></p>
<p>Line1: <input type="text" name="Line1" maxlength="50" /></p>
<p>Line2: <input type="text" name="Line2" maxlength="50" /></p>
<p>City: <input type="text" name="City" maxlength="40" /></p>
</div>
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