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[英]Python2.7 code to extract only strings from list containing unicode characters, blank spaces and square brackets
[英]Remove strings containing only white spaces from list
如何從列表中刪除空字符串? 我試過這樣的:
starring = ['Vashu Bhagnani', 'Khemchand Bhagnani', ' ', 'Jacky Bhagnani', ' ', 'Prashant Shah', ' ']
output = filter(bool, starring)
我想要的輸出:
['Vashu Bhagnani', 'Khemchand Bhagnani', 'Jacky Bhagnani', 'Prashant Shah']
但output
最終與input
相同。 傳遞給filter
的正確功能是什么?
只有空字符串的計算結果為False
因此您需要使用strip()
來刪除任何空格,然后我們可以依賴於非空字符串被評估為true。
>>> starring = ['Vashu Bhagnani', 'Khemchand Bhagnani', ' ', 'Jacky Bhagnani', ' ', 'Prashant Shah', ' ']
>>> starring = filter(lambda name: name.strip(), starring)
>>> starring
['Vashu Bhagnani', 'Khemchand Bhagnani', 'Jacky Bhagnani', 'Prashant Shah']
雖然列表理解可能更容易:
>>> [name for name in starring if name.strip()]
['Vashu Bhagnani', 'Khemchand Bhagnani', 'Jacky Bhagnani', 'Prashant Shah']
您可以刪除尾隨和前導空格,如果只包含那些空格,則會產生空字符串。
列表理解:
l = [x for x in l if x.strip()]
使用filter
和operator.methodcaller
[docs] :
l = filter(operator.methodcaller('strip'), l)
或者更簡單:
l = filter(str.strip, l)
如果您想要向該方法傳遞其他參數, operator.methodcaller
將是唯一的方法。
s = ['Vashu Bhagnani', 'Khemchand Bhagnani', '', 'Jacky Bhagnani', '', 'Prashant Shah', '']
[a for a in s if len(a) > 0]
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