[英]using ajax how to send parameter from 1 jsp page to another servlet
我正在使用azax動態更改jsp頁面,我想將數據從該jsp頁面發送到servlet。 jsp代碼:
<input type="submit" oninput="loadXMLDoc(this.value)" value="ok" name="ok">
<div id="myDiv">
Insert Id:<input id="p1" type="text" name="edit1" value=""style="visibility:hidden" size="30"/>
</div>
function loadXMLDoc(str){
var xmlhttp;
if (window.XMLHttpRequest){// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}else{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function(){
if (xmlhttp.readyState==4 && xmlhttp.status==200){
document.getElementById("myDiv").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("POST","edit?q="+str,true);
xmlhttp.send();
}
Servlet代碼:
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType("text/html;charset=UTF-8");
PrintWriter out = response.getWriter(); Connection conn=null;
String url = "jdbc:mysql://localhost:3306/";
String dbName = "studentdatabase";
String driver = "com.mysql.jdbc.Driver";
String userName = "root";
String password = "1234";
String student=request.getParameter("str");
Statement stmt;out.println(student);
try {
Class.forName(driver).newInstance();
conn = DriverManager.getConnection(url+dbName,userName,password);
String query = "select name1,telephone,email,department from studentinfo where studentid='"+student+"";
stmt = conn.createStatement();
ResultSet rs = stmt.executeQuery(query);
while(rs.next()){
String s = rs.getObject(1).toString();
out.println("<p> " +s+ "</p>");
}
conn.close;
//System.out.println("Disconnected from database");
} catch (Exception e) {
e.printStackTrace();
}
}
即使數據庫中有studentid = student的值,String學生也會顯示null
。
由於您使用的是HTTP-POST,因此必須將參數放入send方法中。
...
var params = "q="+str;
xmlhttp.open("POST", url, true);
xmlHttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");
xmlHttp.setRequestHeader("Content-length", params.length);
xmlHttp.setRequestHeader("Connection", "close");
xmlHttp.send(params);
...
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