如何在mysql查詢中求和的總和

Question

SELECT a.id AS supplier, sum( processed_weight ) AS total_qty
FROM supplier_inward a
INNER JOIN warehouseb ON a.id = b.supplier
WHERE a.master_product_id = '38'
GROUP BY b.supplier

輸出存在

supplier    total_qty
12046      475.00
12482      99.00

輸出需要

total_qty
574.00

這里我需要這個查詢中的總和（total_qty）？ 如何實現這一目標

Answer 1

只需修改GROUP BY ，添加WITH ROLLUP ：

SELECT a.id AS supplier, sum( processed_weight ) AS total_qty
FROM supplier_inward a
  INNER JOIN warehouseb ON a.id = b.supplier
WHERE a.master_product_id = '38'
GROUP BY b.supplier
  WITH ROLLUP

輸出：

supplier    total_qty
12046       475.00
12482        99.00
NULL        574.00

Answer 2

這個怎么樣：

SELECT SUM(iQuery.total_qty) as iTotal
FROM
    (SELECT a.id AS supplier, sum( processed_weight ) AS total_qty
    FROM supplier_inward a
    INNER JOIN warehouseb ON a.id = b.supplier
    WHERE a.master_product_id = '38'
    GROUP BY b.supplier) as iQuery

Answer 3

嘗試

SELECT sum( processed_weight ) AS total_qty
FROM supplier_inward a
INNER JOIN warehouseb ON a.id = b.supplier
WHERE a.master_product_id = '38'

編輯2 - 來自OP的評論更改結果結構：

有關其他列，請嘗試：

SELECT 
X.supplier,
X.total_qty,
(SELECT sum( processed_weight ) 
 FROM supplier_inward a
 INNER JOIN warehouseb ON a.id = b.supplier
 WHERE a.master_product_id = '38') AS totalq
FROM
(
SELECT 
a.id AS supplier, 
sum( processed_weight ) AS total_qty, 
FROM supplier_inward a
INNER JOIN warehouseb ON a.id = b.supplier
WHERE a.master_product_id = '38'
GROUP BY b.supplier) AS X

對於其他行：

SELECT 
a.id AS supplier, 
sum( processed_weight ) AS total_qty
FROM supplier_inward a
INNER JOIN warehouseb ON a.id = b.supplier
WHERE a.master_product_id = '38'
GROUP BY b.supplier
UNION ALL
SELECT null, X.total_qty
FROM
( 
SELECT sum( processed_weight ) AS total_qty
FROM supplier_inward a
INNER JOIN warehouseb ON a.id = b.supplier
WHERE a.master_product_id = '38' ) AS X

Answer 4

嘗試不使用組，因為你想要總結每一件事