Python - 創建超時（kill subprocess）函數的問題

Question

我需要在我的小程序中支持你，它創建一個子進程，這里是10次ping，應該被給定的超時值（5）殺死。 此示例未成功。 你能給我一個提示嗎？

問候。 斯特凡

輸出：

Traceback (most recent call last):
File "./nwcheck.py.work", line 146, in <module>
MyCheck().check().exit()
File "./nwcheck.py.work", line 80, in check
output = process.communicate()
File "/usr/lib/python2.6/subprocess.py", line 701, in communicate
return self._communicate(input)
File "/usr/lib/python2.6/subprocess.py", line 1199, in _communicate
rlist, wlist, xlist = select.select(read_set, write_set, [])
File "./nwcheck.py.work", line 29, in alarm_handler
raise alarm
TypeError: exceptions must be old-style classes or derived from BaseException, not   builtin_function_or_method

碼：

def check(self):

    class Alarm(Exception):
        pass

    def alarm_handler(signum, frame):
        raise alarm

    def get_process_children(pid):
        p = Popen('ps --no-headers -o pid --ppid %d' % pid, shell = True,
                   stdout = PIPE, stderr = PIPE)
        stdout, stderr = p.communicate()
        return [int(p) for p in stdout.split()]
    timeout = 5
    args2 = [
            'ping',
            'localhost',
            '-c 10',
            ]
    process = subprocess.Popen(args2, stdout=subprocess.PIPE, stderr=subprocess.PIPE, env={'LANG':'de_DE@euro'})
    processpid = process.pid
    print processpid
    if timeout != -1:
        signal(SIGALRM, alarm_handler)
        alarm(timeout)
        print 'in timeout abfrage'
    try:
        ## catch stdout and stderr
        output = process.communicate()
        if timeout != -1:
            alarm(0)
            print 'in timeout abfrage 2'
    except Alarm:
        pids = [process.pid]
        print pids
        if kill_tree:
            pids.extend(get_process_children(process.pid))
        for pid in pids:
        # process might have died before getting to this line
        # so wrap to avoid OSError: no such process
            try:
                kill(pid, SIGKILL)
            except OSError:
                pass
        return -9, '', ''

    # Return a response
    return output

Answer 1

您應該使用異常而不是警報：

class AlarmException(Exception): 
    pass 

...

    def alarm_handler(signum, frame):
        raise AlarmException()

另外，不要忘記管道可能會溢出 。 如果進程對stderr和/或stdout產生太多（在某些Linux上> 64k），程序將被阻止。

Answer 2

子進程可以被以下命令殺死：

import os
os.kill(process.pid, signal.SIGKILL)

或者可能：

from subprocess import Popen
Popen.kill()

要么：

from subprocess import Popen
Popen.terminate()

請參閱： http ： //docs.python.org/library/subprocess.html#popen-objects

Answer 3

您的異常名為“ Alarm ，但您正在alarm 。 Python區分大小寫。

您可能希望將Alarm重命名為更具描述性的內容。 像AlarmException或AlarmError這樣簡單的名稱會使代碼更清晰。