[英]Deploying a Jersey 1.11 RESTful Web service in JBoss 6.1 Final (RestEasy already undeployed)
抱歉,文本牆是對的,但是我想透徹一點,以免浪費您的時間,請給StackOverflow-ers親切。 :-)
我已經成功將Tomcat 7中的RESTful Web服務作為war文件部署和測試,因為JBoss使用Tomcat作為組件,所以我(錯誤地)認為部署就像將war文件放入JBoss 6.1服務器/ default一樣簡單。 / deploy目錄,不! 剛開始我遇到一個錯誤,說只允許一個JAX-RS應用程序類,可以通過從Jboss(所有服務器,缺省服務器和標准服務器)中刪除resteasy.deployer(所有服務器,默認服務器和標准服務器)輕松地解決此問題。
現在的問題是,在Jboss啟動期間我收到以下消息:
10:38:07,431 INFO [PackagesResourceConfig] Scanning for root resource and provider classes in the packages:
net.ussouth.incomm.SPIL.resource
10:38:07,486 INFO [WebApplicationImpl] Initiating Jersey application, version 'Jersey: 1.11 12/09/2011 10:27 AM'
10:38:07,718 SEVERE [RootResourceUriRules] The ResourceConfig instance does not contain any root resource classes.
10:38:07,719 ERROR [[/SPIL]] StandardWrapper.Throwable: com.sun.jersey.api.container.ContainerException: The ResourceConfig instance does not contain any root resource classes.
at com.sun.jersey.server.impl.application.RootResourceUriRules.(RootResourceUriRules.java:99) [:1.11]
at com.sun.jersey.server.impl.application.WebApplicationImpl._initiate(WebApplicationImpl.java:1298) [:1.11]
at com.sun.jersey.server.impl.application.WebApplicationImpl.access$700(WebApplicationImpl.java:169) [:1.11]
at com.sun.jersey.server.impl.application.WebApplicationImpl$13.f(WebApplicationImpl.java:775) [:1.11]
at com.sun.jersey.server.impl.application.WebApplicationImpl$13.f(WebApplicationImpl.java:771) [:1.11]
這是WEB-INF / classes目錄下的Resource類:
package net.ussouth.incomm.SPIL.resource;
import javax.ws.rs.Path;
import javax.ws.rs.POST;
import javax.ws.rs.Consumes;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.Produces;
import javax.ws.rs.FormParam;
import org.apache.log4j.Logger;
@Path("/message")
public class MessageResource {
private static Logger log = Logger.getLogger(MessageResource.class);
@POST
@Path("/Search")
@Produces(MediaType.APPLICATION_XML)
@Consumes(MediaType.APPLICATION_FORM_URLENCODED)
public String search(@FormParam("message") String _msgToProvider, @FormParam("provider") String _provData) {
log.info("MesageResource.search method called");
String outVal = null;
try{
ProviderHandler hnd = new ProviderHandler();
outVal = hnd.getOffers(_msgToProvider);
} catch(JAXBException ex) {
...
} catch (SearchException ex) {
...
}
return outVal;
}
}
這是web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID"
version="2.5">
<display-name>Spil</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>SpilMessageService</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>net.ussouth.incomm.SPIL.resource</param-value>
</init-param>
<init-param>
<param-name>log4j-properties-location</param-name>
<param-value>classes/log4j.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>SpilMessageService</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
</web-app>
最后,下面是jboss-web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE jboss-web PUBLIC "-//JBoss//DTD Web Application 2.4//EN" "http://www.jboss.org/j2ee/dtd/jboss-web_4_2.dtd">
<jboss-web>
<context-root>SPIL</context-root>
</jboss-web>
感謝您的任何幫助。 我花了1.5天的時間研究並撞到牆上。
所有你需要的是解釋使用便攜式JAX-RS的部署方法在這里 。 而不是使用程序包掃描,而是使用javax.ws.rs.core.Application的實現強制進行手動掃描
import java.util.HashSet;
import java.util.Set;
import javax.ws.rs.core.Application;
public class MyApplication extends Application {
@Override
public Set<Class<?>> getClasses() {
final Set<Class<?>> classes = new HashSet<Class<?>>();
// register resources
classes.add(MessageResource.class);
return classes;
}
}
然后,更新您的web.xml以使用它。 切記禁用如下所示的安心掃描。
<?xml version="1.0" encoding="UTF-8"?>
<web-app
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID"
version="2.5">
<display-name>Spil</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>SpilMessageService</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>javax.ws.rs.Application</param-name>
<param-value>net.ussouth.incomm.SPIL.resource.MyApplication</param-value>
</init-param>
<init-param>
<param-name>log4j-properties-location</param-name>
<param-value>classes/log4j.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<context-param>
<param-name>resteasy.scan</param-name>
<param-value>false</param-value>
</context-param>
<context-param>
<param-name>resteasy.scan.providers</param-name>
<param-value>false</param-value>
</context-param>
<context-param>
<param-name>resteasy.scan.resources</param-name>
<param-value>false</param-value>
</context-param>
<servlet-mapping>
<servlet-name>SpilMessageService</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
</web-app>
奧爾夫
我也遇到了同樣的問題(Jersey 1.11 + tomcat 7)。 但是在我換成tomcat 6之后,球衣開始起作用了!
我不知道為什么,但是我建議你改變嘗試。
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