[英]How can i convert a from-subquery into a Hibernate Criteria statement
[英]Can I use Hibernate's Criteria to generate a subquery in the from clause?
我們在項目中經常使用Criteria來動態生成查詢。 我真的很喜歡查詢的表達方式。 問題在於,我們發現無法使該特定查詢使用基於clientId的索引,因此我們需要對其進行更改。 這是正常工作的非索引查詢:
public List<EventInstance> getEventInstances(Date from, Date to, Integer clientId) {
Session session = this.getSession();
Criteria criteria = session.createCriteria(EventInstance.class);
if(clientId != null){
criteria.add(Restrictions.disjunction()
.add(Restrictions.eq("clientId", clientId))
.add(Restrictions.eq("team1ClientId", clientId))
.add(Restrictions.eq("team2ClientId", clientId))
);
}
if(from != null){
criteria.add(Restrictions.ge("startTime", from));
}
if(to != null){
criteria.add(Restrictions.le("startTime", to));
}
@SuppressWarnings("unchecked")
List<EventInstance> events = criteria.list();
this.releaseSession(session);
return events;
}
該查詢只能使用startTime索引,而不能與任何clientId一起使用索引。 我發現以下查詢形式有效地使用了我們的索引,並且我想使用條件創建此查詢:
select * from ( select * from eventInstance where (clientId = 8 or team1ClientId = 8 or team2ClientId = 8) ) evtalias where evtalias.startTime < now()
我已經可以使用以下代碼在WHERE子句中進行子選擇:
public List<EventInstance> getEventInstances(Date from, Date to, Integer clientId){
Session session = this.getSession();
DetachedCriteria subSelectClient = DetachedCriteria.forClass(EventInstance.class);
if(clientId != null){
subSelectClient.add(Restrictions.disjunction()
.add(Restrictions.eq("clientId", clientId))
.add(Restrictions.eq("team1ClientId", clientId))
.add(Restrictions.eq("team2ClientId", clientId))
)
.setProjection(Property.forName("id"));
}
Criteria criteria = session.createCriteria(EventInstance.class);
if(clientId != null){
criteria.add(Property.forName("id").in(subSelectClient));
}
if(from != null){
criteria.add(Restrictions.ge("startTime", from));
}
if(to != null){
criteria.add(Restrictions.le("startTime", to));
}
@SuppressWarnings("unchecked")
List<EventInstance> events = criteria.list();
this.releaseSession(session);
return events;
}
這將生成如下查詢:
select * from eventInstance this_ where this_.id in (select this_.id as y0_ from eventInstance this_ where (this_.clientId=8 or this_.team1ClientId=8 or this_.team2ClientId=8)) and this_.startTime<=now();
使用索引比我的原始查詢更糟,並且不會在FROM中進行子選擇。
所以我的問題是,我可以按標准執行此操作嗎?還是堅持使用HQL甚至本機SQL。 或者,如果您知道如何創建可以解決我的問題的索引,但是從mysql文檔中了解到,這是不可能的。
這是我要創建的目標查詢的explain的輸出:
mysql> explain select * from ( select * from eventInstance where (clientId = 8 or team1ClientId = 8 or team2ClientId = 8) ) evtalias where evtalias.startTime < now();
+----+-------------+---------------+-------------+-------------------------------+----- ------------------+---------+------+------+------------------------------------------------ --------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+---------------+-------------+-------------------------------+-----------------------+---------+------+------+--------------------------------------------------------------+
| 1 | PRIMARY | <derived2> | ALL | NULL | NULL | NULL | NULL | 288 | Using where |
| 2 | DERIVED | eventInstance | index_merge | eijoin2,ei_client,team2,team1 | ei_client,team1,team2 | 5,5,5 | NULL | 300 | Using union(ei_client,team1,team2); Using where; Using index |
+----+-------------+---------------+-------------+-------------------------------+-----------------------+---------+------+------+--------------------------------------------------------------+
2 rows in set (0.00 sec)
這是來自休眠標准子查詢的解釋:
+----+--------------------+-------+-----------------+---------------------------------------+---------+---------+------+-------+-------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+--------------------+-------+-----------------+---------------------------------------+---------+---------+------+-------+-------------+
| 1 | PRIMARY | this_ | ALL | ei3 | NULL | NULL | NULL | 49434 | Using where |
| 2 | DEPENDENT SUBQUERY | this_ | unique_subquery | PRIMARY,eijoin2,ei_client,team2,team1 | PRIMARY | 4 | func | 1 | Using where |
+----+--------------------+-------+-----------------+---------------------------------------+---------+---------+------+-------+-------------+
2 rows in set (0.00 sec)
據我所知, Criteria
和HQL都無法在from
子句中生成帶有子查詢的查詢,因此您必須使用本機SQL。
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