[英]manipulating img src with regex -php
我該如何替換它:
http://example.com/myfolder/files/year/month/imagename-widthxheight.imageextension
對此:
http://example.com/myfolder/files/year/month/imagename-300x300.imageextension
任何幫助?
你可能想試試這個
// if your src has widthxheight are specified literally like that you may try
echo preg_replace("/\W{0,1}(width).*(height)/i","-300x300","http://www.mysite.com/myfolder/files/year/month/imagename-widthxheight.imageextension");
// if your src has widthxheight are specified in int val you may try
echo preg_replace("/\W{0,1}(\d{1,7}).*(\d{1,7})/i","-300x300","http://www.mysite.com/myfolder/files/year/month/imagename-123x456.imageextension");
實際值-300x300將根據您的實際需求而有所不同。 所以我認為最好通過變量傳遞這些值。
怎么樣:
$new_img = preg_replace("~([^/]+)-widthxheight(\.[^.]+)$~i","$1-300x300$2",
"http://www.mysite.com/myfolder/files/year/month/imagename-widthxheight.imageextension");
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