[英]json issue with google apis and jquery
嘿,我有以下代碼給我一個錯誤:“ Uncaught SyntaxError:Unexpected token:”
我的代碼:
$.getJSON("http://maps.googleapis.com/maps/api/place/details/json?reference="+ref_tel+"&sensor=true&key=MY_API_KEY&callback=?",
function(data){
}, "json");
怎么了?
PS JSON如下所示:
{
"html_attributions" : [],
"result" : {
"address_components" : [
{
"long_name" : "48",
"short_name" : "48",
"types" : [ "street_number" ]
},
{
"long_name" : "Pirrama Road",
"short_name" : "Pirrama Road",
"types" : [ "route" ]
},
{
"long_name" : "Pyrmont",
"short_name" : "Pyrmont",
"types" : [ "locality", "political" ]
},
{
"long_name" : "NSW",
"short_name" : "NSW",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "AU",
"short_name" : "AU",
"types" : [ "country", "political" ]
},
{
"long_name" : "2009",
"short_name" : "2009",
"types" : [ "postal_code" ]
}
],
"formatted_address" : "5/48 Pirrama Road, Pyrmont NSW, Australia",
"formatted_phone_number" : "(02) 9374 4000",
"geometry" : {
"location" : {
"lat" : -33.8669710,
"lng" : 151.1958750
}
},
"icon" : "http://maps.gstatic.com/mapfiles/place_api/icons/generic_business-71.png",
"id" : "4f89212bf76dde31f092cfc14d7506555d85b5c7",
"international_phone_number" : "+61 2 9374 4000",
"name" : "Google Sydney",
"rating" : 4.60,
"reference" : "CnRlAAAAAfV6JIqSzL8Cf4VnXn0EaI1d5k3IPhdkEonq0MxiUbQFFSVuptVbXbNH4mrevb0bc7G8yWqTUv76i4KTuO_Wf3OrRHjCJJwzQ0mNLjbYGSVqy2eqyrgOUkl6S_sJfTbHzWZYrfPy7KZaet0mM5S6thIQJYuy5v_JD--ZxXEJLWTQRRoU5UaciXBBo89K-bce18Ii9RsEIws",
"types" : [ "store", "establishment" ],
"url" : "http://maps.google.com/maps/place?cid=10281119596374313554",
"vicinity" : "5/48 Pirrama Road, Pyrmont",
"website" : "http://www.google.com.au/"
},
"status" : "OK"
}
調試器向我顯示錯誤在第2行。有人可以解決此問題嗎?
Google Maps Places API似乎不支持JSONP 。 因此,您將無法在客戶端使用它(如果將API密鑰放在源代碼中的某個位置,您還將公開它)。
順便說一句,由於
{
"something" : value
}
被解釋為代碼塊(語句)而不是對象(表達式)。 Javascript具有帶有以下語法的標簽:
labelName : statement
但是只能將標識符用作標簽名稱。 字符串(或更一般地說,任何表達式)不能。 這導致語法錯誤。
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