如何在此SQL查詢中獲取值大於3分鍾的行？

Question

如何在此查詢中使Diff_In_Secs高於180秒？

select trunc(a.RECEIVED_TS) day, 
       to_char(avg(extract(minute from b.RECEIVED_TS - a.RECEIVED_TS)*60 + extract(second from b.RECEIVED_TS - a.RECEIVED_TS)), '999.99') Diff_In_Secs, 
       count(*)
  from nps_request a, 
       nps_reply b
 where a.id = b.ID
   and a.RECEIVED_TS > trunc(sysdate) - 10
   and b.target_id is not null
   and b.RECEIVED_TS is not null
group by trunc(a.RECEIVED_TS)
order by trunc(a.RECEIVED_TS) desc;

Answer 1

用選擇符包裝查詢：

SELECT * FROM ( 
    select trunc(a.RECEIVED_TS) day, to_char(avg(extract(minute from b.RECEIVED_TS - a.RECEIVED_TS)*60 + extract(second from b.RECEIVED_TS - a.RECEIVED_TS)), '999.99') Diff_In_Secs, count(*)
    from nps_request a, nps_reply b
    where a.id = b.ID
    and a.RECEIVED_TS > trunc(sysdate) - 10
    and b.target_id is not null
    and b.RECEIVED_TS is not null
    group by trunc(a.RECEIVED_TS)
    order by trunc(a.RECEIVED_TS) desc;
) AS A WHERE A.Diff_In_Secs > 180