浮動值除以目標C中的誤差

Question

當我運行這段代碼時：

float angle = startAngle;
int i = 0;

for (float f = self.minNumber; f <= self.maxNumber; f += minorTickIncrement) {
    points[i++] = CGPointMake(centerX + cos(angle) * (radius - tickInset), centerY + sin(angle) * (radius - tickInset));

    CGFloat myTickLength;

    NSLog(@"f : %f",f);
    NSLog(@"tickIncrement : %f",tickIncrement);
    NSLog(@"f / tickIncrement : %f",f / tickIncrement);
    NSLog(@"(int)(f / tickIncrement) : %d",(int)(f / tickIncrement));
    NSLog(@"(f / tickIncrement - (int)(f / tickIncrement)) : %f",(f / tickIncrement - (int)(f / tickIncrement)));
    NSLog(@"fabs((f / tickIncrement - (int)(f / tickIncrement))) : %f",fabs((f / tickIncrement - (int)(f / tickIncrement))));

    float checkValue = (f / tickIncrement - (int)(f / tickIncrement));

    if (fabs(checkValue) < 0.05) { // if is major tick
        myTickLength = self.tickLength;
        NSString *string = [[NSString alloc] initWithFormat:@"%0.1f", f];
        float textWidth = textHeight * [string length] / 2;
        CGContextShowTextAtPoint(ctx, centerX + cos(angle) * (radius - textInset) - textWidth / 2.0, centerY + sin(angle) * (radius - textInset) + textHeight / 4.0, [string UTF8String], [string length]);
        [string release];

    } else {
        myTickLength = self.minorTickLength;
    }

    points[i++] = CGPointMake(centerX + cos(angle) * (radius - myTickLength - tickInset), centerY + sin(angle) * (radius - myTickLength - tickInset));

    angle += minorTickAngleIncrement;
}

顯示以下輸出：

 f : 0.100000
 tickIncrement : 0.100000
 f / tickIncrement : 1.000000
 (int)(f / tickIncrement) : 1
 (f / tickIncrement - (int)(f / tickIncrement)) : 0.000000
  fabs((f / tickIncrement - (int)(f / tickIncrement))) : 0.000000

  f : 0.120000
 tickIncrement : 0.100000
 f / tickIncrement : 1.200000
 (int)(f / tickIncrement) : 1
 (f / tickIncrement - (int)(f / tickIncrement)) : 0.200000
 fabs((f / tickIncrement - (int)(f / tickIncrement))) : 0.200000

 f : 0.140000
 tickIncrement : 0.100000
 f / tickIncrement : 1.400000
 (int)(f / tickIncrement) : 1
 (f / tickIncrement - (int)(f / tickIncrement)) : 0.400000
 fabs((f / tickIncrement - (int)(f / tickIncrement))) : 0.400000

 f : 0.160000
 tickIncrement : 0.100000
 f / tickIncrement : 1.600000
 (int)(f / tickIncrement) : 1
 (f / tickIncrement - (int)(f / tickIncrement)) : 0.600000
 fabs((f / tickIncrement - (int)(f / tickIncrement))) : 0.600000

 f : 0.180000
 tickIncrement : 0.100000
 f / tickIncrement : 1.800000
 (int)(f / tickIncrement) : 1
 (f / tickIncrement - (int)(f / tickIncrement)) : 0.800000
 fabs((f / tickIncrement - (int)(f / tickIncrement))) : 0.800000

 f : 0.200000
 tickIncrement : 0.100000
 f / tickIncrement : 2.000000
 **(int)(f / tickIncrement) : 1**
 (f / tickIncrement - (int)(f / tickIncrement)) : 1.000000
 fabs((f / tickIncrement - (int)(f / tickIncrement))) : 1.000000

...................

在哪里，您可以看到在輸出(int)(f / tickIncrement) : 1的最后一個塊中(int)(f / tickIncrement) : 1必須返回2，但返回1。

為什么會這樣？

Answer 1

最有可能的是，您遇到了浮點表示法問題。
嘗試使用double，但是知道它不會解決根本的問題，您看到的2.0實際上是1.99999 ...只是被格式化為顯示2.0

閱讀“ 每位計算機科學家應了解的浮點運算法則 ”

在此期間，請嘗試簡單地使用：

(int)(f / tickIncrement + tickIncrement / 5.0)