[英]tcp/ip open connection
目前我正在使用以下代碼與服務器交互
public String connectToserverforincomingmsgs(String phonurl, String phno)
throws IOException {
URL url = new URL(phonurl);
HttpURLConnection con = (HttpURLConnection) url.openConnection();
con.setDoInput(true);
// Allow Outputs
con.setDoOutput(true);
con.connect();
BufferedWriter writer = null;
writer = new BufferedWriter(new OutputStreamWriter(
con.getOutputStream(), "UTF-8"));
// give server your all parameters and values (replace param1 with you
// param1 name and value with your one's)
writer.write("sender_no=" + phno);
writer.flush();
String responseString = "";
BufferedReader reader = null;
reader = new BufferedReader(new InputStreamReader(con.getInputStream()));
String line;
while ((line = reader.readLine()) != null) {
responseString = responseString.concat(line);
}
con.disconnect();
return responseString;
}
我怎么能建立 tcp 連接。現在我不知道。 我也是 android 和 java 的新手,所以任何關於 tcp 連接的示例代碼都將不勝感激
要創建 TCP 連接,您需要使用 Socket:
Socket socket = new Socket(host_name_or_ip_address, port_no);
發送數據使用socket.getOutputStream()
接收數據使用socket.getInputStream()
只需將 HttpURLConnection 替換為 Socket。 它的工作原理幾乎相同
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