如何在兩個單獨的字符串中找到匹配的單詞？

Question

如果有兩個單獨的字符串，則需要檢索數組中所有匹配的單詞（在這些字符串中）。 而且此匹配應該不區分大小寫。 實現這一目標的最有效方法是什么。

例如：

NSString *s1 = @"Hello there, I want to match similar words.";  
NSString *s2 = @"Do you really want to match word, hello?";  

結果array應包含"hello", "want", "to", "match" 。

我經歷了許多問題，並且像正則表達式一樣通過網絡進行響應， 以匹配不包含單詞的行？ ，但沒有找到所需的解決方案。

Answer 1

嘗試這個：

NSString *s1 = @"Hello there, I want to match similar words.";  
NSString *s2 = @"Do you really Want to match word, hello?";
NSCharacterSet *separatorSet = [NSCharacterSet characterSetWithCharactersInString:@" ?.,"];
NSArray *as1 = [[s1 lowercaseString] componentsSeparatedByCharactersInSet:separatorSet];
NSArray *as2 = [[s2 lowercaseString] componentsSeparatedByCharactersInSet:separatorSet];

NSMutableSet* set1 = [NSMutableSet setWithArray:as1];
NSMutableSet* set2 = [NSMutableSet setWithArray:as2];

[set1 intersectSet:set2];
[set1 removeObject:@""];
NSArray* result =[set1 allObjects];
NSLog(@"%@",result);

Answer 2

您可以為此使用NSMutableSet 。

    NSString *s1 = @"Hello there, I want to match similar words.";  
    NSString *s2 = @"Do you really want to match word, hello?"; 

    NSArray *components = [s1 componentsSeparatedByString:@" "];
    NSArray *components1 = [s2 componentsSeparatedByString:@" "];
    NSLog(@"%@",components);
    NSLog(@"%@",components1);

    NSMutableSet *resultSet = [NSMutableSet setWithArray:components1];
    NSSet *setA = [NSSet setWithArray:components];
    [resultSet intersectSet:setA];
    NSArray *result = [resultSet allObjects];
    NSLog(@"%@",result);

如果您的句子中沒有標點符號，則此解決方案將為您工作。如果您希望帶標點符號的句子有效，只需刪除句子中的所有標點符號即可。

Answer 3

NSString *s1 = @"Hello there, I want to match similar words.";  
NSString *s2 = @"Do you really want to match word, hello?";  

NSCharacterSet *separatorSet = [NSCharacterSet characterSetWithCharactersInString:@" ?.,"];
NSArray *s1Array = [s1 componentsSeparatedByCharactersInSet:separatorSet];
NSArray *s2Array = [s2 componentsSeparatedByCharactersInSet:separatorSet];

NSMutableArray *resultArray = [NSMutableArray arrayWithCapacity:0];
for(int index = 0; index < [s1Array count]; index++){
    NSString *compareString = [[s1Array objectAtIndex:index] lowercaseString];

    NSUInteger findIndex = [s2Array indexOfObjectPassingTest:^BOOL(id obj, NSUInteger idx, BOOL *stop) {

        NSString *currentString = (NSString *)obj;
        if([[currentString lowercaseString] isEqualToString:compareString] &&
           ![currentString isEqualToString:@""]){
            return YES;
            *stop = YES;
        }else{
            return NO;
        }

    }
                            ];
    if(findIndex !=NSNotFound){
        [resultArray addObject:compareString];
    }
}
NSLog(@"Result:%@",[resultArray description]);

Answer 4

嘗試以下代碼

NSString *s1 = @"Hello there, I want to match similar words.";  
        NSString *s2 = @"Do you really want to match word, hello?";
        NSCharacterSet *doNotWant = [[NSCharacterSet letterCharacterSet] invertedSet];
        NSArray *array1 = [[s1 uppercaseString] componentsSeparatedByCharactersInSet:doNotWant];
        NSArray *array2 = [[s2 uppercaseString] componentsSeparatedByCharactersInSet:doNotWant];

        NSSet *set1 = [[NSSet alloc] initWithArray:array1];
        NSMutableSet *set2 = [[NSMutableSet alloc] initWithArray:array2];
        [set2 intersectSet:set1];
        NSLog(@"set2:%@",set2);
        NSLog(@"set1:%@",set1);
        NSArray *aray_res = [set2 allObjects];
        NSLog(@"aray_res:%@",aray_res);