帶有where子句的SQL MIN函數

Question

這是我的項目表

 Project Table
JNo Name    City
J1  Proj1   London
J2  Proj2   Paris
J3  Proj3   Athens
J4  Proj4   India

這是我的貨運表

Shipment
SNo PNo JNo Qty
S1  P1  J1  50
S1  P1  J2  90
S1  P2  J1  40
S1  P3  J3  20
S2  P1  J3  110
S2  P2  J2  30
S2  P4  J3  10
S2  P3  J1  100
S3  P1  J3  80
S3  P4  J2  70
S3  P4  J2  70
S4  P1  J3  20
S4  P2  J1  60

我想要提供最小數量的項目名稱。

我試過了。 但它只返回最小數值，這是我的代碼

select min(qty) from shipment where jno IN(select jno from project)

Answer 1

SELECT p.name 
FROM Project p, Shipment s
WHERE s.JNo = p.JNo
  AND s.Qty in (SELECT MIN(qty) FROM shipment)

Answer 2

不使用MIN：

    SELECT p.Name, s.Qty
    FROM `project` p
    INNER JOIN `shipment` s ON `p`.`jno` = `s`.`jno`
    ORDER BY `s`.`qty` ASC
    LIMIT 1

Answer 3

這應該像你說的那樣工作

select p.Name, s.Qty 
from Project p, Shipment s
where p.Jno=s.Jno
and s.Qty in(select min(s.Qty) from Shipment s);

將從顯示項目名稱Project從表和最小數量shipment表。

Answer 4

您應該使用的查詢是

SELECT project.Name, min(qty) FROM Project 
LEFT JOIN Shipment ON project.JNO = Shipment.JNO

我希望這可以幫到你。

Answer 5

對於發貨量最小的項目，請嘗試：

select p.name
from project p
join shipment s on p.jno=s.jno
order by s.qty
limit 1

對於總出貨量最小的項目，請嘗試：

select name from
(select p.name, sum(s.qty) total_shipped
 from project p
 join shipment s on p.jno=s.jno
 group by p.name
 order by 2) sq
limit 1