[英]Use regular expression to find/replace substring in NSString
我想使用正則表達式來查找正則表達式模式的每個實例Ie &*;
在我的字符串中刪除它,因此返回值是沒有任何匹配的原始字符串。 也想使用相同的函數來匹配單詞之間的多個空格,而是使用單個空格。 找不到這樣的功能。
示例輸入字符串
NSString *str = @"123 &1245; Ross Test 12";
返回值應該是
123 Ross Test 12
如果符合此模式的任何內容"&*
或多個空格並將其替換為@"";
NSString *string = @"123 &1245; Ross Test 12";
NSError *error = nil;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"&[^;]*;" options:NSRegularExpressionCaseInsensitive error:&error];
NSString *modifiedString = [regex stringByReplacingMatchesInString:string options:0 range:NSMakeRange(0, [string length]) withTemplate:@""];
NSLog(@"%@", modifiedString);
字符串在String擴展中使用regex替換代碼
Objective-C的
@implementation NSString(RegularExpression)
- (NSString *)replacingWithPattern:(NSString *)pattern withTemplate:(NSString *)withTemplate error:(NSError **)error {
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern
options:NSRegularExpressionCaseInsensitive
error:error];
return [regex stringByReplacingMatchesInString:self
options:0
range:NSMakeRange(0, self.length)
withTemplate:withTemplate];
}
@end
解決
NSString *string = @"123 &1245; Ross Test 12";
// remove all matches string
NSString *result = [string replacingWithPattern:@"&[\\d]+?;" withTemplate:@"" error:nil];
// result = "123 Ross Test 12"
或者更多
NSString *string = @"123 + 456";
// swap number
NSString *result = [string replacingWithPattern:@"([\\d]+)[ \\+]+([\\d]+)" withTemplate:@"$2 + $1" error:nil];
// result = 456 + 123
Swift2
extension String {
func replacing(pattern: String, withTemplate: String) throws -> String {
let regex = try NSRegularExpression(pattern: pattern, options: .CaseInsensitive)
return regex.stringByReplacingMatchesInString(self, options: [], range: NSRange(0..<self.utf16.count), withTemplate: withTemplate)
}
}
Swift3
extension String {
func replacing(pattern: String, withTemplate: String) throws -> String {
let regex = try RegularExpression(pattern: pattern, options: .caseInsensitive)
return regex.stringByReplacingMatches(in: self, options: [], range: NSRange(0..<self.utf16.count), withTemplate: withTemplate)
}
}
使用
var string = "1!I 2\"want 3#to 4$remove 5%all 6&digit and a char right after 7'from 8(string"
do {
let result = try string.replacing("[\\d]+.", withTemplate: "")
} catch {
// error
}
// result = "I want to remove all digit and a char right after from string"
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