為什么在 64 位機器上使用 uint8_t 編寫的這段代碼比使用 uint32_t 或 uint64_t 編寫的類似代碼運行得更快? [英]Why does this piece of code written using uint8_t run faster than analogous code written with uint32_t or uint64_t on a 64bit machine?
std::bitset<64> 是否適用於 uint64_t 的 32 位機器? [英]Does std::bitset<64> work on 32 bit machines for uint64_t?
將包含 32 位值的 uint64_t 傳遞給參數實際上是 uint32_t 的外部 function 是否安全? [英]Is it safe to pass a uint64_t containing a 32-bit value to an external function whose parameter is actually a uint32_t?
uint64_t的未定義高階,同時移位和屏蔽32位值 [英]Undefined high-order of uint64_t while shifting and masking 32-bit values
在x86機器上移位超過32位的uint64_t整數未定義的行為? [英]Is Shifting more than 32 bits of a uint64_t integer on an x86 machine Undefined Behavior?
將兩個 uint32_t 轉換為 uint64_t,然后根據位模式而不是值轉換回 double [英]Turn two uint32_t into a uint64_t, then turn back into a double based on the bit pattern not the value