帶注釋的Spring MVC 3驗證 - 不顯示形式：錯誤

Question

我已經堅持了大約一個小時，這不是我第一次這樣做，但我無法弄明白。

它應該顯示表單錯誤，而不是拋出此異常。

LE：我在此期間設法解決了異常，但我仍然無法看到錯誤。 他們沒有呈現

org.springframework.web.util.NestedServletException：請求處理失敗; 嵌套異常是org.springframework.validation.BindException：org.springframework.validation.BeanPropertyBindingResult：1 errors字段'name'上對象'category'中的字段錯誤：被拒絕的值[jk]; 代碼[Range.category.name，Range.name，Range.java.lang.String，Range]; arguments [org.springframework.context.support.DefaultMessageSourceResolvable：codes [category.name，name]; 參數[]; 默認消息[name]，25,3]; 默認消息[gfhghj] org.springframework.web.servlet.FrameworkServlet.processRequest（FrameworkServlet.java:894）org.springframework.web.servlet.FrameworkServlet.doPost（FrameworkServlet.java:789)javax.servlet.http.HttpServlet.service （HttpServlet.java:637)javax.servlet.http.HttpServlet.service(httpServlet.java:717)org.springframework.security.web.FilterChainProxy $ VirtualFilterChain.doFilter（FilterChainProxy.java:311)org.springframework.security.web .access.intercept.FilterSecurityInterceptor.invoke（FilterSecurityInterceptor.java:116）org.springframework.security.web.access.intercept.FilterSecurityInterceptor.doFilter（FilterSecurityInterceptor.java:83）org.springframework.security.web.FilterChainProxy $ VirtualFilterChain.doFilter （FilterChainProxy.java:323）org.springframework.security.web.access.ExceptionTranslationFilter.doFilter（ExceptionTranslationFilter.java:113）org.springframework.security.web.FilterChainProxy $ VirtualFilterChain.doFilter（FilterChainProxy.java:323)org.springfr amework.security.web.session.SessionManagementFilter.doFilter（SessionManagementFilter.java:101）org.springframework.security.web.FilterChainProxy $ VirtualFilterChain.doFilter（FilterChainProxy.java:323）org.springframework.security.web.authentication.AnonymousAuthenticationFilter。 doFilter（AnonymousAuthenticationFilter.java:113）org.springframework.security.web.FilterChainProxy $ VirtualFilterChain.doFilter（FilterChainProxy.java:323）org.springframework.security.web.servletapi.SecurityContextHolderAwareRequestFilter.doFilter（SecurityContextHolderAwareRequestFilter.java:54）org。 springframework.security.web.FilterChainProxy $ VirtualFilterChain.doFilter（FilterChainProxy.java:323）org.springframework.security.web.savedrequest.RequestCacheAwareFilter.doFilter（RequestCacheAwareFilter.java:45）org.springframework.security.web.FilterChainProxy $ VirtualFilterChain。 doFilter（FilterChainProxy.java:323）org.springframework.security.web.authentication.www.BasicAuthenticationFilter.doFilter（BasicAuthenticat ionFilter.java:150)org.springframework.security.web.FilterChainProxy $ VirtualFilterChain.doFilter（FilterChainProxy.java:323）org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.doFilter（AbstractAuthenticationProcessingFilter.java:182)org.springframework。 security.web.FilterChainProxy $ VirtualFilterChain.doFilter（FilterChainProxy.java:323）org.springframework.security.web.authentication.logout.LogoutFilter.doFilter（LogoutFilter.java:105）org.springframework.security.web.FilterChainProxy $ VirtualFilterChain。 doFilter（FilterChainProxy.java:323）org.springframework.security.web.context.SecurityContextPersistenceFilter.doFilter（SecurityContextPersistenceFilter.java:87）org.springframework.security.web.FilterChainProxy $ VirtualFilterChain.doFilter（FilterChainProxy.java:323）org。 springframework.security.web.FilterChainProxy.doFilter（FilterChainProxy.java:173）org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate（DelegatingFilterProxy.java:346）org。 springframework.web.filter.DelegatingFilterProxy.doFilter（DelegatingFilterProxy.java:259）org.springframework.web.filter.HiddenHttpMethodFilter.doFilterInternal（HiddenHttpMethodFilter.java:77）org.springframework.web.filter.OncePerRequestFilter.doFilter（OncePerRequestFilter.java： 76）org.springframework.web.filter.CharacterEncodingFilter.doFilterInternal（CharacterEncodingFilter.java:88）org.springframework.web.filter.OncePerRequestFilter.doFilter（OncePerRequestFilter.java:76）

@Controller
@RequestMapping("/category")
public class CategoryController {

@Autowired
StockGateway stockGateway;

@RequestMapping(value = "add", method = RequestMethod.POST)
public String addCategory(@Valid @ModelAttribute("category") CategoryAdd category, ModelMap model,
        BindingResult binding) {

    if (binding.hasErrors()) {
        return "category.add";
    }
    CategoryDTO dto = Converter.toCategory(category);
    try {
        stockGateway.createCategory(dto);
    } catch (StockGatewayException e) {
        e.printStackTrace();
    }
    return "redirect:/category/add";

}

@RequestMapping(value = "add", method = RequestMethod.GET)
public String initView(ModelMap model) {
    model.put("category", new CategoryAdd());
    return "category.add";
}

}

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<div xmlns:jsp="http://java.sun.com/JSP/Page" 
xmlns:spring="http://www.springframework.org/tags"
 xmlns:c="http://java.sun.com/jsp/jstl/core" 
 xmlns:security = "http://www.springframework.org/security/tags"
 xmlns:util="urn:jsptagdir:/WEB-INF/tags/util"
 xmlns:form="http://www.springframework.org/tags/form"
 version="2.0">

<security:authorize access="hasRole('ROLE_STOCK')" var="isStock">
    <form:form modelAttribute="category"  method="POST" action="add"  >
            <table>
            <tr>
                <td>Name  :</td> <td> <form:input path="name" /></td>
            </tr>
            <tr>
                <td></td> <td> <form:errors path="name" cssClass="error" /></td>
            </tr>
            </table>
            <form:button>Add</form:button>
    </form:form>
</security:authorize>

public class CategoryAdd {

@Range(min= 3 , max = 25, message="gfhghj")
private String name;



public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

Answer 1

似乎必須依賴於映射控制器方法中必須列出參數的順序。
例如：

public String addCategory(@Valid CategoryAdd category,BindingResult result, 
Map map)

會工作，而：

public String addCategory(@Valid CategoryAdd category, Map map, 
BindingResult result)

將不會。 我不完全理解為什么會這樣，特別是因為它編譯沒有任何問題。

Answer 2

完整的解決方案是：

public String addCategory(@Valid CategoryAdd category,BindingResult result,
        Map map
        ) {

    if (result.hasErrors()) {
        map.put("categoryAdd", (CategoryAdd)result.getTarget());
        return "category.add";
    }
    CategoryDTO dto = Converter.toCategory(category);
    try {
        stockGateway.createCategory(dto);
    } catch (StockGatewayException e) {
        e.printStackTrace();
    }
    return "redirect:/category/add";

注意我用Map改變了參數ModelMap，如果結果有錯誤，我從結果中放回模型。

現在WTF：BindingResult有一個字段objectName，其值為類的名稱。 您必須將modelAttribute / commandName設置為該值。 與BindingResult中的objectName相同，否則它不會呈現錯誤。 所以要匹配它：

    <form:form modelAttribute="categoryAdd" commandName="categoryAdd"  method="POST" action="add"  >

有誰知道我們如何從BindingResult更改objectName？ 默認情況下，它將采用類的名稱。