函數內的Python無限while循環

Question

無論我嘗試什么，我都會通過此函數不斷獲得無限循環：

  # Excercise 33 - LPTHW

i = 0 
numbers = []

#Ec 1
#numb = 6
#iplus = 10

def theloop(numb):
        global i
        #i = 0
        #number = []
        while i < numb:
            print "At the top of i is %d" % i
            numbers.append(i)

            i = i + 1
            print "Numbers now: ", numbers
            print "At the bottom i is %d" % i

        print "The numbers: "

        for num in numbers:
            print num

theloop(7)

當我運行腳本時，它只會繼續打印：

At the top of i is 0
At the top of i is 0
...

提前致謝。

Answer 1

您的代碼對我來說是書面的，但由於使用了混合的制表符和空格，因此看起來有些奇怪。 當我使用.readlines閱讀腳本時，您會看到以下內容：

 '    def theloop(numb):\n',
 '    \t\tglobal i\n',
 '    \t\t#i = 0\n',
 '            #number = []\n',
 '    \t\twhile i < numb:\n',
 '     \t\t\tprint "At the top of i is %d" % i\n',
 '        \t\tnumbers.append(i)\n',
 '    \n',
 '        \t\ti = i + 1\n',

因此，我建議到處切換到四個空間，然后再移到另一個空間。 請注意，print語句和append / increment語句之間的制表符數量有所不同。

Answer 2

如果您混合使用空格和制表符，則嘗試像這樣運行腳本：

python -tt yourscript.py ##this will raise error if you've mixed spaces and tabs

這是運行腳本后得到的，不是無限的。

At the top of i is 0
Numbers now:  [0]
At the bottom i is 1
At the top of i is 1
Numbers now:  [0, 1]
At the bottom i is 2
At the top of i is 2
Numbers now:  [0, 1, 2]
At the bottom i is 3
At the top of i is 3
Numbers now:  [0, 1, 2, 3]
At the bottom i is 4
At the top of i is 4
Numbers now:  [0, 1, 2, 3, 4]
At the bottom i is 5
At the top of i is 5
Numbers now:  [0, 1, 2, 3, 4, 5]
At the bottom i is 6
At the top of i is 6
Numbers now:  [0, 1, 2, 3, 4, 5, 6]
At the bottom i is 7
The numbers: 
0
1
2
3
4
5
6

Answer 3

在以下幾行之后，似乎出現了縮進錯誤：

   while i < numb:
        print "At the top of i is %d" % i
        numbers.append(i)

就像James所說的那樣，在粘貼時它在這里工作得很好，因此您可能需要檢查實際代碼中的縮進級別是否正確。