在兩個JavaScript函數之間切換
[英]Switch between two javascript functions
問題描述
基本上，我希望php決定網站的哪個版本加載以下內容：
<?php
$sql="SELECT _1 FROM Player_Registry WHERE Player_Name = $_SESSION[user_name]";
$result_1=mysql_query($sql);
if($result_1 < 10) { ?>
<script type="text/javascript">
function setdescription_1() {
document.getElementById('title_box').innerHTML = 'Alchemist';
}
</script>
<?php
}
else {
?>
<script type="text/javascript">
function setdescription_1() {
document.getElementById('title_box').innerHTML = 'Master Alchemist';
}
</script>
<?php
}?>
問題是它們都運行，所以即使我將條件設置為true，我仍然會得到第二個。
據我所知，完整的源代碼與正在查看的源代碼完全相同，但是站點預覽中沒有顯示任何php（實際上是存在的，因為我的另一台計算機可以查看站點而沒有看到php）但是當它查看源代碼時，可以看到它不應該看到的代碼）：
<head>
<title>Blank</title>
<link rel="icon" type="image/png" href="Pictures/favicon.png">
<meta name="description" content="" />
<meta name="keywords" content="" />
<meta name="author" content="" />
<meta name="owner" content="" />
<meta name="copyright" content="" />
<meta http-equiv="content-type" content="text/html;charset=UTF-8" />
<link rel="stylesheet" href="TreeStyle.css" type="text/css" />
</head>
<body>
<div style="width:100%; height:12.5%;">
<p style="font-size: 300%;"><b>Skill Tree: Alchemist</b></p>
</div>
<div style="width:100%; height:75%;">
<?php
$sql="SELECT _1 FROM Player_Registry WHERE Player_Name = $_SESSION[user_name]";
$result_1=mysql_query($sql);
if($result_1 < 10)
{
?>
<script type="text/javascript">
function setdescription_1()
{
document.getElementById('title_box').innerHTML = 'Alchemist';
document.getElementById('desc_box').innerHTML = 'Turn surroundings into base element costs.';
}
</script>
<?php
}
else
{
?>
<script type="text/javascript">
function setdescription_1()
{
document.getElementById('title_box').innerHTML = 'Master Alchemist';
document.getElementById('desc_box').innerHTML = 'Equiped Philosopher's Stone allows bypass of element costs.';
}
</script>
<?php
}
$sql="SELECT _2 FROM Player_Registry WHERE Player_Name = $_SESSION[user_name]";
$result_2=mysql_query($sql);
if($result_2 < 10)
{
?>
<script type="text/javascript">
function setdescription_2()
{
document.getElementById('title_box').innerHTML = 'Learn Runes';
document.getElementById('desc_box').innerHTML = 'Create Runes and Cores up to Lv.<?php echo "$result_2" ?>';
}
</script>
<?php
}
else
{
?>
<script type="text/javascript">
function setdescription_2()
{
document.getElementById('title_box').innerHTML = 'Comprehension';
document.getElementById('desc_box').innerHTML = 'Create Runes and Cores up to Lv.10';
}
</script>
<?php
}
?>
<script type="text/javascript">
function cleardescription()
{
document.getElementById('title_box').innerHTML = 'Skill Name';
document.getElementById('desc_box').innerHTML = 'This is the skill description.';
}
</script>
<table>
<tr>
<td></td>
<td><a href='AddSkillPoints.php?skill=_1' onmouseover="setdescription_1()" onmouseout="cleardescription()"><img src="Alchemist.png" /></a></td>
<td><img src="Blank_Tile.png"/></td>
<td><a href='AddSkillPoints.php?skill=_2' onmouseover="setdescription_2()" onmouseout="cleardescription()"><img src="Learn_Runes.png"/></td>
etc..............
</table>
</div>
<div style="width:100%; height:12.5%;">
<b><p id="title_box" style="font-size: 150%;">Skill Name</p></b><br />
<p id="desc_box">This is the skill description.</p>
</div>
</div>
</body>
</html>
1 個解決方案
解決方案1
1 已采納 2012-03-27 07:18:09
我不相信如果您的PHP實際被解析，您不會兩者兼得。 如果未解析，則查看網頁的源代碼后，您將看到與粘貼的代碼完全相同的代碼
確保php被解析-如果沒有，那就是問題所在。
除非您必須發布不允許標簽的處理，否則腳本標簽通常不會干擾解析-例如，如果您使用某種框架，而該框架不應該輸入php而是一些標記化的代碼
這是一個更好的示例-請注意，我將腳本移到了頭部，但並沒有真正進行優化-因此，如果您在一次調用中獲得兩個值並創建一個對象數組，則php可能會更加優雅
<?PHP
$sql="SELECT _1 FROM Player_Registry WHERE Player_Name = $_SESSION[user_name]";
$result_1=mysql_query($sql);
$sql="SELECT _2 FROM Player_Registry WHERE Player_Name = $_SESSION[user_name]";
$result_2=mysql_query($sql);
%><html>
<head>
<title>Blank</title>
<link rel="icon" type="image/png" href="Pictures/favicon.png">
.
.
<meta http-equiv="content-type" content="text/html;charset=UTF-8" />
<link rel="stylesheet" href="TreeStyle.css" type="text/css" />
<script type="text/javascript">
var result1 = parseInt("<?PHP echo $result_1; ">,10);
var skillLevel = (result1>=10?'Master ':'')+'Alchemist';
var skillDesc = result1>=10?"Equipped with Philosopher´s Stone allows bypass of element costs.":"Turn surroundings into base element costs.";
var runeLevel = result2>=10?'Comprehension':'Learn Runes';
var runeDesc = 'Create Runes and Cores up to Lv.'+result2;
window.onload=function() {
setdescription_1();
}
function setdescription_1() {
document.getElementById('title_box').innerHTML = skillLevel;
document.getElementById('desc_box').innerHTML = skillDesc;
}
function setdescription_2() {
document.getElementById('title_box').innerHTML = runeLevel;
document.getElementById('desc_box').innerHTML = runeDesc;
}
function cleardescription() {
document.getElementById('title_box').innerHTML = 'Skill Name';
document.getElementById('desc_box').innerHTML = 'This is the skill description.';
}
</script>
</head>
在兩個PHP函數之間隨機切換
聲明:本站的技術帖子網頁，遵循CC BY-SA 4.0協議，如果您需要轉載，請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.