兩列中的最小值（Oracle SQL）

Question

現在搜索了一段時間，但沒有找到適合我的問題的答案。

說明：

ID | Year |  Factor1 | Number1 | Number2
1  | 2010 |   213    |    1     |   1     
2  | 2010 |   213    |    1     |   2    
3  | 2010 |   214    |    2     |   1    
4  | 2010 |   214    |    2     |   2    
6  | 2010 |   210    |    3     |   1    
7  | 2010 |   210    |    3     |   2   
8  | 2011 |   250    |    3     |   5 
5  | 2012 |   214    |    2     |   4

編輯：忘記了什么，更正了上表中的內容。 我需要2個組合：year和factor1僅一次，然后是min（number1）和最后一個min（number2）。 例如，在上面我需要ID 1、3、5、6、8（很抱歉，它們混合在一起以提高其他值的可讀性）。

有人知道如何實現嗎？

Answer 1

SELECT id , year, number1, number2 
FROM @table A
WHERE number1 IN (SELECT MIN(number1) FROM @table WHERE year = A.year)
OR number2 IN (SELECT MIN(number2) FROM @table WHERE year = A.year)

@table是您的表

Answer 2

現在從另一個論壇獲得了代碼，對我來說效果很好：

SELECT 
  tab.*
FROM
  t33 tab
  INNER JOIN (
    SELECT
      m1.y,
      m1.factor1,
      m1.min_1,
      m2.min_2
    FROM
      (
        SELECT
          y,
          factor1,
          MIN(number1) AS min_1
        FROM
          t33 tab
        GROUP BY
          y,
          factor1
      ) m1
      INNER JOIN (
        SELECT 
              y,
              factor1,
              number1,
              MIN(number2) AS min_2
            FROM 
              t33
            GROUP BY
              y,
              factor1,
              number1
        ) m2
      ON m1.y = m2.y
      AND m1.factor1 = m2.factor1
      AND m1.min_1 = m2.number1
    ) sel
      ON tab.y = sel.y
      AND tab.factor1 = sel.factor1
      AND tab.number1 = sel.min_1
      AND tab.number2 = sel.min_2

Answer 3

好，這樣的事嗎？

delete from mb_test
where ID not in
   ( select id
     from mb_test mbt
         ,(select year, min(number1) as min1, min(number2) as min2
           from mb_test
           group by year) mb_mins
     where mbt.year = mb_mins.year
     and   (mbt.number1 = mb_mins.min1 OR mbt.number2 = mb_mins.min2)
   )