SQL 查詢內部連接 Select

Question

我想編寫一個 SQL 查詢，如下所示。 它的語法不正確。 我該如何糾正它？

$sql_package_feature = "SELECT f.feature_id, f.feature_name FROM  tbl_feature f 
LEFT JOIN SELECT * FROM tbl_feature_and_profile fp WHERE fp.profile_id= ? ) ON 
f.feature_id = fp.feature_id AND f.package_id = fp.package_id WHERE fp.feature_id 
IS NULL  AND f.package_id = ? ORDER BY f.feature_id";

Answer 1

我認為這是在子選擇之后缺少'as fp'。 試試這個查詢：

SELECT 
      f.feature_id, 
      f.feature_name 
FROM  tbl_feature f 
LEFT JOIN (SELECT * FROM tbl_feature_and_profile fp WHERE fp.profile_id= ? ) 
     as fp ON (f.feature_id = fp.feature_id AND f.package_id = fp.package_id) 
WHERE 
     fp.feature_id IS NULL  AND f.package_id = ? ORDER BY f.feature_id

Answer 2

如果你加入一個子選擇，你必須給它命名。 將名稱放在子選擇上而不是其中的表：

SELECT f.feature_id, f.feature_name
FROM  tbl_feature f
LEFT JOIN (
  SELECT *
  FROM tbl_feature_and_profile
  WHERE profile_id= ?
) fp ON f.feature_id = fp.feature_id AND f.package_id = fp.package_id
WHERE fp.feature_id IS NULL AND f.package_id = ?
ORDER BY f.feature_id

Answer 3

您沒有為第二個表命名，但您稍后會在 ON 子句中使用它。 右括號后缺少fp ：

SELECT f.feature_id, f.feature_name 
FROM  tbl_feature f
LEFT JOIN (
    SELECT *
    FROM tbl_feature_and_profile fp 
    WHERE fp.profile_id= ?
) fp
ON      f.feature_id = fp.feature_id 
    AND f.package_id = fp.package_id
WHERE   fp.feature_id IS NULL
    AND f.package_id = ?
ORDER BY f.feature_id"
;

Answer 4

嘗試沒有嵌套 SELECT 語句的 JOIN，只有表名。 嘗試：

$sql_package_feature = 
"SELECT f.feature_id, f.feature_name 
FROM  
tbl_feature f 
LEFT JOIN 
tbl_feature_and_profile fb
ON f.feature_id = fp.feature_id AND f.package_id = fp.package_id 
WHERE fp.feature_id IS NULL  AND f.package_id = ? AND fp.profile_id = ? ORDER BY f.feature_id";