根據另一個表的值對表進行 mysql 查詢

Question

我有以下查詢並且工作正常。 如果您看到查詢，您會注意到有一個名為$code的變量，我曾經像這樣手動設置它的值$code="1001";

function check1() { 

$code="1001";

 $getData = $this->db->query("SELECT * FROM vouchers 
 LEFT JOIN  details on vouchers.voucher_no = details.voucher_no 
LEFT JOIN   accounts on accounts.code = vouchers.account_code 
WHERE (voucher_type='1' AND t_code=$code)

 UNION ALL

SELECT * FROM vouchers 
LEFT JOIN details on vouchers.voucher_no = details.voucher_no 
LEFT JOIN   accounts on accounts.code = details.t_code 
 WHERE (voucher_type='0' AND account_code=$code)

 ");

       if($getData->num_rows() > 0)
        return $getData->result_array();
        else
        return null;
}

當我在我的視圖文件中顯示結果時，我使用以下腳本：

  <?php if(count($records) > 0) { ?>

  <?php $i = $this->uri->segment(3) + 0; foreach ($records as $row){ $i++; ?>

  <?php echo $row['voucher_date']; ?>  
  <?php echo $row['name']; ?> 
  <?php echo $row['amount']; ?>    <br>

<?php  } ?>

<?php } else { echo "No Record Found";} ?>

<?php 
$sum = 0;
foreach ( $records as $row ) {
 $sum += str_replace(",", "", $row['amount']);
}
?> 

  Total: <?php  echo  number_format( $sum, 2 );?>

現在我想要做的是從下面的 mysql 表中獲取$code的值並獲取其所有值的結果，這樣當我在視圖文件中顯示結果時它不會顯示$code="1001"的結果$code="1001"不僅適用於$code="1002" ， $code="1003" 。

為了實現我想要的，我必須更改上面的 mysql 查詢。但我不知道該怎么做，請你告訴我。

提前致謝：）

表名：accounts

code   name 
1001    Cash Account
1002    Advertising Expense
1003    Accounts Receivable

Answer 1

SELECT * FROM vouchers 
 LEFT JOIN  details on vouchers.voucher_no = details.voucher_no 
LEFT JOIN   accounts on accounts.code = vouchers.account_code 
WHERE voucher_type='1' AND t_code IN (SELECT * FROM code_table)

 UNION ALL

SELECT * FROM vouchers 
LEFT JOIN details on vouchers.voucher_no = details.voucher_no 
LEFT JOIN   accounts on accounts.code = details.t_code 
 WHERE voucher_type='0' AND account_code IN (SELECT * FROM code_table)