使用http.send（）Ajax

Question

if(document.getElementById(callerName).checked) {
    //alert(callerName);        
    var poststr = "field=" + escape(encodeURI(callerName)) +
      "&op=add" + "&nocache=" + nocache;
}
else {
    //alert(callerName);
    var poststr = "field=" + escape(encodeURI(callerName)) + 
      "&op=del" + "&nocache=" + nocache;
}
http.send(poststr);

當我收到$_POST['field']我得到'％20'哪里有空格..任何解決方案來獲取確切的字符串？

Answer 1

PHP：

$field = urldecode($_POST['field']);

Answer 2

您正在使用escape和encodeURI雙重轉義數據。 另外，我建議您改用encodeURIComponent 。 嘗試更改為此：

var poststr = "field=" + encodeURIComponent(callerName) + 
  "&op=add&nocache=" + nocache;