通過PHP從mysql中獲取數據，然后將具有相似列值和計數的行分組
[英]Fetch data from mysql via PHP, then group rows with similar column values and count
問題描述
我基本上有這個程序從數據庫中獲取訂單。 我的問題是我需要以這樣一種方式生成一個報告，即腳本將獲得具有相同列值的行，然后計算它們並顯示它們。
說表'訂單'
salesorder family product 1111111 pi_gx af000 1111111 pi_gx af000 1111112 sfng af111 1111113 pi_gx af000
將顯示在我的php頁面中
sales order family qty product 1111111 pi_gx 2 af000 1111112 sfng 1 af111 1111113 pi_gx 1 af000
它計算所述銷售訂單的行數並顯示數量，同時在我的頁面中僅顯示該銷售訂單的單個副本。
這是代碼：
<body class="printable"><h1 align="center">New Orders Dropped for Product Integration 1X</h1>
<table align="center" width="100%">
<tr>
<td class="labels">Prepared: </td>
<td class="boxed"><?php date_default_timezone_set("Asia/Singapore");$today = date("d/m/y H:i");echo $today; ?></td>
<td class="divider"> </td>
<td class="labels">Time Coverage: </td>
<td class="boxed">12:00 to 2:00</td>
<td class="divider"> </td>
<td class="labels">BirthStamp: </td>
<td class="boxed">5/21/2012</td>
<td class="divider"> </td>
<td class="labels">Saved: </td>
<td class="boxed"><?php echo $today; ?></td>
</tr>
<tr>
<td class="labels">Prepared by (Production): </td>
<td><input type="text" name="preparer" id="preparer" class="boxedPrepared" /></td>
<td class="divider"></td>
<td class="labels">Recorded by (Store): </td>
<td><input type="text" name="recorder" id="recorded" class="boxedPrepared" /></td>
<td class="divider"></td>
<td class="labels">Recorded: </td>
<td class="boxed" colspan="3"><?php echo $today; ?></td>
</tr>
</table>
<br />
<?php
$conn = mysql_connect("localhost", "root", "123456") or die(mysql_error());
mysql_select_db("store") or die(mysql_error());
$sql = mysql_query("SELECT * FROM report ORDER BY salesorder AND masterproduct ASC") or die(mysql_error());
if(mysql_num_rows($sql) == 0) {
echo "<center><b>No ORDER/S in Queue</b></center>";
} else {
echo "
<table width=\"100%\" border=\"0\" cellspacing=\"0\" cellpadding=\"0\" align=\"center\" class=\"data\">
<tr>
<td class=\"dataHeader\">Sales Order</td>
<td class=\"dataHeader\">Sales Order Code</td>
<td class=\"dataHeader\">Family</td>
<td class=\"dataHeader\">Product Code</td>
<td class=\"dataHeader\">Quantity</td>
<td class=\"dataHeader\">Birth Stamp</td>
<td class=\"dataHeader\">Due Date</td>
</tr>
";
while($result = mysql_fetch_array($sql)) {
echo "
<tr>
<td class=\"data\">".$result['salesorder']."</td>
<td class=\"data\"><span class=\"title\">*".$result['salesorder']."*</span><br />".$result['salesorder']."</td>
<td class=\"data\">".$result['family']."</td>
<td class=\"data\"><span class=\"title\">*".$result['masterproduct']."*</span><br />".$result['masterproduct']."</td>
<td class=\"data\">";
//need to echo the value here
echo "</td>
<td class=\"data\">".$result['birthstamp']."</td>
<td class=\"data\"><span class=\"title\">*".$result['duedate']."*</span><br />".$result['duedate']."</td>
</tr>
";
}
echo "</table>";
}
?>
3 個解決方案
解決方案1
1 已采納 2012-05-24 07:08:53
SELECT salesorder, family, product, COUNT() AS qty FROM orders
GROUP BY salesorder;
編輯：好的，嘗試這個大小：
SELECT r.*, t.qty FROM report r LEFT JOIN
(SELECT salesorder, COUNT() AS qty FROM orders
GROUP BY salesorder) t
ON t.salesorder=r.salesorder
ORDER BY r.salesorder AND r.masterproduct ASC
解決方案2
1 2012-05-24 07:09:33
試試這個查詢：
SELECT
COUNT() AS qty, sales_order, family, products
FROM orders
GROUP BY sales_order
解決方案3
0 2012-05-25 03:29:12
終於想通了。 謝謝你們的幫助。 我將我的SQL查詢更改為：
$sql = mysql_query("SELECT salesorder, masterproduct, family, birthstamp, duedate, COUNT( * ) AS total FROM report WHERE family = '$family' AND birthstamp BETWEEN '$startDT' AND '$endDT' GROUP BY salesorder, masterproduct, family, duedate ");
它工作正常！
有條件地計算MYSQL列行（多個數據庫）並通過PHP輸出數據
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從數據庫（MySQL）獲取同一列的兩行不同值的行
[英]Fetch two rows of different values of the same column from database (MySQL)
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