原則 2：將數據插入到具有關聯的實體中

Question

通過在向數據庫中添加新實體時添加條件來解決，它檢查實體是否不為空……顯然有空實體試圖保存。 現在控制器代碼如下所示：

...
$ciudades_id = explode(';', $this->getRequest()->getParam('ciudades_id'));
           foreach($ciudades_id as $ciudad_id){
               $ciudad = $this->_em->find("Application_Model_Ciudades", intval($ciudad_id));
               if($ciudad!= null){
                $carrera->getCiudad()->add($ciudad);                  
               }
           }


           $instituciones_id = explode(';', $this->getRequest()->getParam('instituciones_id'));
           foreach($instituciones_id as $institucion_id){
               $institucion = $this->_em->find("Application_Model_Instituciones", intval($institucion_id));
               if($institucion != null){
                  $carrera->getInstituciones()->add($institucion); 
               }
           }
...

感謝在#doctrine IRC 頻道提供幫助的人:)

---

這是我的問題...我得到了一個名為“Carreras”（職業）的實體，它有一些關聯，並且新的職業通過 Web 表單添加到數據庫中。 職業對我來說是一個測試，有問題和其他屬性，用戶可以選擇申請該測試的城市和機構。

因此，當我嘗試在實體上保存新數據時出現此錯誤：

An error occurred
Application error
Exception information:

Message: A new entity was found through the relationship
'Application_Model_Carreras#ciudad' that was not configured 
to cascade persist operations for entity: Doctrine\ORM\UnitOfWork@. 
Explicitly persist    the new entity or configure cascading persist 
operations on the relationship. If you cannot find out which entity 
causes the problem implement 'Application_Model_Ciudades#__toString()' 
to get a clue.

這是“Carreras”的模型

use Doctrine\Common\Collections\ArrayCollection;
/**
 * @Entity
 * @Table(name="carreras")
 */
class Application_Model_Carreras
{
    /**
     * @Id @Column(type="integer")
     * @GeneratedValue
     */
    private $id;

    /** @Column(type="string") */
    private $nombre;

    /**
     * @ManyToMany(targetEntity="Application_Model_PruebasCarrera")
     * @JoinTable(name="Carreras_PruebasCarrera",
     *      joinColumns={@JoinColumn(name="carreras_id", referencedColumnName="id")},
     *      inverseJoinColumns={@JoinColumn(name="pruebascarrera_id", referencedColumnName="id")}
     *      )
     */
    private $pruebas;


    /** @Column(type="integer") */
    private $valor;

    /** @Column(type="date") */
    private $fechainicio;

    /** @Column(type="date") */
    private $fechafin;

    /**
     * This association causes error
     * @ManyToMany(targetEntity="Application_Model_Ciudades")
     * @JoinTable(name="carrera_ciudades",
     *      joinColumns={@JoinColumn(name="carrera_id", referencedColumnName="id")},
     *      inverseJoinColumns={@JoinColumn(name="ciudad_id", referencedColumnName="id")}
     *      )
     */
    private $ciudad;

    /**
     * @ManyToMany(targetEntity="Application_Model_Instituciones")
     * @JoinTable(name="carrera_instituciones",
     *      joinColumns={@JoinColumn(name="carrera_id", referencedColumnName="id")},
     *      inverseJoinColumns={@JoinColumn(name="institucion_id", referencedColumnName="id")}
     *      )
     */
    private $instituciones;

    public function __construct()
    {
        $this->pruebas = new ArrayCollection();
        $this->ciudad = new ArrayCollection();
        $this->instituciones = new ArrayCollection();
    }

    public function setNombre($nombre){
        $this->nombre = $nombre;
    }

    public function setValor($valor){
        $this->valor = $valor;
    }

    public function setFechainicio($fechainicio){
        $this->fechainicio = $fechainicio;
    }

    public function setFechafin($fechafin){
        $this->fechafin = $fechafin;
    }

    public function getCiudad(){
        return $this->ciudad;
    }

    public function getPruebas(){
        return $this->pruebas;
    }

    public function getInstituciones(){
        return $this->instituciones;
    }
}

現在控制器的動作：

 /*
     * This is an action for adding a new career
     */
    public function agregarAction()
    {
       $formtest = new Admin_Form_AgregarCarrera();
       $this->view->formtest = $formtest;
       if ($this->getRequest()->isPost() && $this->view->formtest->isValid($this->_getAllParams()))
       {
           /*
            * If the form is okay creating new Carreer model object
            * This model has some attributes and three associations (for now) 
            * you can see them later in detail
            */
           $carrera = new Application_Model_Carreras();
           $carrera->setNombre($this->getRequest()->getParam("nombre"));
           $carrera->setValor($this->getRequest()->getParam("valor"));
           $carrera->setFechainicio(new \DateTime($this->getRequest()->getParam("fechainicio")));
           $carrera->setFechafin(new \DateTime($this->getRequest()->getParam("fechafin")));
           /*
            * This is the first association. It's working fine (for now)
            */
           $pruebas = $this->getRequest()->getParam("pruebas");
           foreach($pruebas as $prueba){
              if($prueba != '0'){
                  $tmp = $this->_em->find("Application_Model_PruebasCarrera", $prueba);
                  $carrera->getPruebas()->add($tmp);
              }
           }
           /*
            * This is the second associations, i'm getting the error with this one
            */
           $ciudades_id = explode(';', $this->getRequest()->getParam('ciudades_id'));
           foreach($ciudades_id as $ciudad_id){
               $ciudad = $this->_em->find("Application_Model_Ciudades", intval($ciudad_id));
               $carrera->getCiudad()->add($ciudad);
           }
           /*
            * This is the third one. Nothing to say about this.
            */
           $instituciones_id = explode(';', $this->getRequest()->getParam('instituciones_id'));
           foreach($instituciones_id as $institucion_id){
               $institucion = $this->_em->find("Application_Model_Instituciones", intval($institucion_id));
               $carrera->getInstituciones()->add($institucion);
           }

           $this->_em->persist($carrera);
           $this->_em->flush();
           //$this->redirector->gotoSimpleAndExit('index','Carrera','admin');     
        }
    }

好吧，我不知道還有什么要展示的……如果您能幫助我，請發表評論:)

- 編輯

我在模型“Carreras”的關聯中添加了 cascade={"persist"} 並且錯誤發生了變化：

An error occurred
Application error
Exception information:

Message: Class Doctrine\ORM\UnitOfWork is not a 
valid entity or mapped super class. 

現在這是“Ciudades”模型，它存儲可用於測試的城市，並與存在於每個城市的機構相關聯。

use Doctrine\Common\Collections\ArrayCollection;
/**
 * @Entity
 * @Table(name="ciudades")
 */
class Application_Model_Ciudades {
    /**
     * @Id @Column(type="integer")
     * @GeneratedValue
     */
    private $id;

    /** @Column(type="string") */
    private $ciudad;

    /** @Column(type="string") */
    private $departamento;

    /** @Column(type="string") */
    private $pais;

    /**
     * @ManyToMany(targetEntity="Application_Model_Instituciones")
     * @JoinTable(name="Ciudades_Instituciones",
     *      joinColumns={@JoinColumn(name="ciudades_id", referencedColumnName="id")},
     *      inverseJoinColumns={@JoinColumn(name="instituciones_id", referencedColumnName="id")}
     *      )
     */
    private $instituciones;

    public function __construct()
    {
        $this->instituciones = new ArrayCollection();
    }

    public function getCiudad(){
        return $this->ciudad;
    }

    public function getId(){
        return $this->id;
    }

    public function getInstituciones(){
        return $this->instituciones;
    }

}

現在這是“Instituciones”模型，它存儲可用於測試的機構。

/**
 * @Entity
 * @Table(name="instituciones")
 */
class Application_Model_Instituciones {
    /**
     * @Id @Column(type="integer")
     * @GeneratedValue
     */
    private $id;

    /** @Column(type="string") */
    private $nombre;

    public function getId(){
        return $this->id;
    }

    public function getNombre(){
        return $this->nombre;
    }

}

現在這是“PruebasCarrera”模型，對我來說這個模型實體存儲了測試的問題，每個問題都可以有一個支持該問題的合作伙伴：

use Doctrine\Common\Collections\ArrayCollection;
/**
 * @Entity
 * @Table(name="pruebas_carrera")
 */
class Application_Model_PruebasCarrera extends Application_Model_PruebasBase{

    /**
     * @Id @Column(type="integer")
     * @GeneratedValue
     */
    private $id;

    /**
     * @ManyToMany(targetEntity="Application_Model_Patrocinadores")
     * @JoinTable(name="pruebascarrera_patrocinadores",
     *      joinColumns={@JoinColumn(name="pruebas_id", referencedColumnName="id", unique="true")},
     *      inverseJoinColumns={@JoinColumn(name="patrocinadores_id", referencedColumnName="id", unique=false)}
     *      )
     */
    protected $patrocinadores;

    /** @Column(type="string") */
    private $respuesta; 

    public function __construct() {
        $this->patrocinadores = new ArrayCollection();
    }

    public function setRespuesta($respuesta){
        $this->respuesta = $respuesta;
    }

    public function getPatrocinadores(){
        return $this->patrocinadores;
    }

    public function getId(){
        return $this->id;
    }

    public function getRespuesta(){
        return $this->respuesta;
    }

}

Answer 1

請出示相關實體代碼：Application_Model_Ciudades Application_Model_PruebasCarrera Application_Model_Instituciones

此時看https://www.doctrine-project.org/projects/doctrine-orm/en/2.6/reference/working-with-associations.html#transitive-persistence-cascade-operations

此時我認為您應該將 cascade={"persist"} 添加到 Application_Model_Ciudades 實體。