[英]Get most recent date from an array of dates in "Y-m-d H:i:s" format
我有Ymd H:i:s
格式的日期數組,例如:
array(5) {
[0]=> string(19) "2012-06-11 08:30:49"
[1]=> string(19) "2012-06-07 08:03:54"
[2]=> string(19) "2012-05-26 23:04:04"
[3]=> string(19) "2012-05-27 08:30:00"
[4]=> string(19) "2012-06-08 08:30:55"
}
我想知道最近的日期。
換句話說,今天是 2012 年 6 月 13 日,哪個日期時間最接近今天的日期?
從我的示例數組中,我期待2012-06-11 08:30:49
。
我怎樣才能做到這一點?
使用max()
, array_map()
和strtotime()
。
$max = max(array_map('strtotime', $arr));
echo date('Y-m-j H:i:s', $max); // 2012-06-11 08:30:49
做一個循環,將值轉換為日期,並將最新的值存儲在var中。
$mostRecent= 0;
foreach($dates as $date){
$curDate = strtotime($date);
if ($curDate > $mostRecent) {
$mostRecent = $curDate;
}
}
類似的東西...你明白了如果你想要最近的BEFORE今天:
$mostRecent= 0;
$now = time();
foreach($dates as $date){
$curDate = strtotime($date);
if ($curDate > $mostRecent && $curDate < $now) {
$mostRecent = $curDate;
}
}
按日期對數組進行排序,然后獲取數組的前值。
$dates = array(5) { /** omitted to keep code compact */ }
$dates = array_combine($dates, array_map('strtotime', $dates));
arsort($dates);
echo $dates[0];
$dates = [
"2012-06-11 08:30:49"
,"2012-06-07 08:03:54"
,"2012-05-26 23:04:04"
,"2012-05-27 08:30:00"
,"2012-06-08 08:30:55"
];
echo date("Y-m-d g:i:s",max(array_map('strtotime',$dates)));
那是我的變種。 它適用於未來的日期。
$Dates = array(
"2012-06-11 08:30:49",
"2012-06-07 08:03:54",
"2012-05-26 23:04:04",
"2012-05-27 08:30:00",
"2012-06-08 08:30:55",
"2012-06-12 07:45:45"
);
$CloseDate = array();
$TimeNow = time();
foreach ($Dates as $Date) {
$DateToCompare = strtotime($Date);
$Diff = $TimeNow - $DateToCompare;
if ($Diff < 0) $Diff *= -1;
if (count($CloseDate) == 0) {
$CloseDate['Date'] = $Date;
$CloseDate['Diff'] = $Diff;
continue;
}
if ($Diff < $CloseDate['Diff']) {
$CloseDate['Date'] = $Date;
$CloseDate['Diff'] = $Diff;
}
}
var_dump($CloseDate);
我相信,以下是查找最近日期的最短代碼。 您可以更改它以查找最近日期的索引或查找將來或過去的最近日期。
$Dates = array(
"2012-06-11 08:30:49",
"2012-06-07 08:03:54",
"2012-05-26 23:04:04",
"2012-05-27 08:30:00",
"2012-06-08 08:30:55",
"2012-06-22 07:45:45"
);
$close_date = current($Dates);
foreach($Dates as $date)
if( abs(strtotime('now') - strtotime($date)) < abs(strtotime('now') - strtotime($close_date)))
$close_date = $date;
echo $close_date;
這是我的建議:
$most_recent = 0;
foreach($array as $key => $date){
if( strtotime($date) < strtotime('now') && strtotime($date) > strtotime($array[$most_recent]) ){
$most_recent = $key;
}
}
print $array[$most_recent]; //prints most recent day
$arrayy = array(
"2012-06-11 08:30:49","2012-06-07 08:03:54","2012-05-26 23:04:04",
"2012-05-27 08:30:00","2012-06-08 08:30:55"
);
function getMostRecent($array){
$current = date("Y-m-d h:i:s");
$diff1 = NULL;
$recent = NULL;
foreach($array as $date){
if($diff = strcmp($current,$date)){
if($diff1 == NULL){
$diff1 = $diff;
$recent = $date;
}
else{
if($diff < $diff1){
$diff1 = $diff;
$recent = $date;
}
}
}
}
return $recent;
}
嘗試這個:
public function getLargerDate(array $datas) {
$newDates = array();
foreach($datas as $data){
$newDates[strtotime($data)] = $data;
}
return $newDates[max(array_keys($newDates))];
}
試試這個100%的作品
function getRecentDate($date_list,$curDate){
$curDate = strtotime($curDate);
$mostRecent = array();
foreach($date_list as $date){
$diff = strtotime($date)-$curDate;
if($diff>0){
$mostRecent[$diff] = $date;
}
}
if(!empty($mostRecent)){
ksort($mostRecent);
$mostRecent_key = key($mostRecent);
if($mostRecent_key){
return $mostRecent[$mostRecent_key];
}
}else{
return false;
}
}
$date_list = array('15-05-2015','14-01-2015','18-03-2015','20-10-2016','12-12-2014','12-12-2015');
$curDate = '14-01-2015';
$get_recent = getRecentDate($date_list,$curDate);
if($get_recent){
echo $get_recent;
}else{
echo 'No recent date exists';
}
經過近 10 年和近 50,000 次瀏覽量,似乎沒有人能從樹上看到森林。
日期時間戳數組的格式非常適合簡單的字符串比較。 絕對沒有理由調用max()
以外的任何東西來獲取最高/最新的字符串。 您的Ymd H:i:s
格式化值可以作為字符串進行比較,因為單位整數是從最大幅度到最小幅度排列的。 所有整數都始終用零填充。 從字面上看,不需要任何准備。
代碼:(演示)
$dates = [
"2012-06-11 08:30:49",
"2012-06-07 08:03:54",
"2012-05-26 23:04:04",
"2012-05-27 08:30:00",
"2012-06-08 08:30:55",
];
echo max($dates);
// 2012-06-11 08:30:49
$DatesList = array( '2015-05-19', '2015-09-17', '2015-09-24', '2015-10-02', '2015-10-23', '2015-11-12', '2015-12-25' );
$counter = 0;
$currentDate = date("Y-m-d");
foreach ($DatesList as $dates)
{
if($dates >= $currentDate)
{
$storeDates[$counter] = $dates;
$counter++;
}
}
$closestDate = current($storeDates);
echo $closestDate;
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