減少try的數量，除了在python中

Question

我正在編寫一個類似於診斷程序的程序，它運行一個測試，然后基於那個做更多的測試，因此大多數這些都在`try,except中完成`try,except並且有很多它們。 有沒有其他方法來實現這一點，但減少try except ？

這是一個示例代碼。

try:
    treeinfo = subprocess.check_output(['C:\Python27\Scripts\scons.bat','-f' ,'scons_default.py' ,'--tree=all'])
    print "\n"
    print "Your machine type is ",platform.machine()
        print "Compiling using default compiler\n"
    print treeinfo

except subprocess.CalledProcessError as e:
    print "ERROR\n"

try:
    with open ('helloworld.exe')as f:
        subprocess.call('helloworld.exe')
        print"Build success"
        log64 =  subprocess.check_output(["dumpbin", "/HEADERS", "helloworld.exe"])
        if arch64 in log64:
            print "Architecture of the compiled file is 64-bit "
        elif arch32 in log64:
            print "Architecture of the compiled file is 32-bit"
except IOError as e:
    print "Build failed\n"


print "\n"

上面的相同代碼（具有不同的文件名）重復，我知道這樣做不是一個好習慣。 我對python很新，google搜索沒有給出任何有用的結果。

Answer 1

您可以將邏輯拆分為單獨的函數，並在try塊中逐個調用它們：

def a():
    treeinfo = subprocess.check_output(['C:\Python27\Scripts\scons.bat','-f' ,'scons_default.py' ,'--tree=all'])
    print "\n"
    print "Your machine type is ",platform.machine()
    print "Compiling using default compiler\n"
    print treeinfo

def b():
    subprocess.call('helloworld.exe')
    print"Build success"

def c():
    log64 =  subprocess.check_output(["dumpbin", "/HEADERS", "helloworld.exe"])
    if arch64 in log64:
        print "Architecture of the compiled file is 64-bit "
    elif arch32 in log64:
        print "Architecture of the compiled file is 32-bit"

def try_these(funs, catch):
    for fun in funs:
        try:
            fun()
        except catch:
            print 'ERROR!'

try_these([a, b, c], catch=(IOError, OSError))

在哪里“捕獲”你想要處理的異常元組。