[英]Exception in thread “main” java.lang.IllegalArgumentException: setSelectedIndex: 4 out of bounds
[英]Exception in thread “main” java.lang.IllegalArgumentException: Sheet index (0) is out of range (0..-1)
我想使用apache poi api在java中讀取2010 excel文件...但是它給我一個錯誤線程“main”中的異常java.lang.IllegalArgumentException:Sheet index(0)超出范圍(0 ..- 1 )我正在使用xssf,但如果我想從excel的舊格式獲取數據然后它通過唱HSSF工作正常..我不知道XSSF會發生什么...我的代碼..plz幫助我。
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.InputStream;
import java.util.Iterator;
import org.apache.poi.ss.usermodel.Cell;
import org.apache.poi.ss.usermodel.Row;
import org.apache.poi.xssf.usermodel.XSSFCell;
import org.apache.poi.xssf.usermodel.XSSFRichTextString;
import org.apache.poi.xssf.usermodel.XSSFRow;
import org.apache.poi.xssf.usermodel.XSSFSheet;
import org.apache.poi.xssf.usermodel.XSSFWorkbook;
/**
* This java program is used to read the data from a Excel file and display them
* on the console output.
*
* @author dhanago
*/
public class xssff {
/** Creates a new instance of POIExcelReader */
public xssff() {
}
/**
* This method is used to display the Excel content to command line.
*
* @param xlsPath
*/
@SuppressWarnings("unchecked")
public void displayFromExcel(String xlsPath) {
InputStream inputStream = null;
try {
inputStream = new FileInputStream(xlsPath);
} catch (FileNotFoundException e) {
System.out.println("File not found in the specified path.");
e.printStackTrace();
}
XSSFWorkbook workBook = new XSSFWorkbook();
XSSFSheet sheet = workBook.getSheetAt(1);
Iterator<Row> rows = sheet.rowIterator();
while (rows.hasNext()) {
XSSFRow row = (XSSFRow) rows.next();
// display row number in the console.
System.out.println();
// once get a row its time to iterate through cells.
Iterator<Cell> cells = row.cellIterator();
while (cells.hasNext()) {
XSSFCell cell = (XSSFCell) cells.next();
/*
* Now we will get the cell type and display the values
* accordingly.
*/
switch (cell.getCellType()) {
case XSSFCell.CELL_TYPE_NUMERIC: {
// cell type numeric.
System.out.print(cell.getNumericCellValue() + "\t\t\t");
break;
}
case XSSFCell.CELL_TYPE_STRING: {
// cell type string.
XSSFRichTextString richTextString = cell
.getRichStringCellValue();
System.out.print(richTextString.getString() + "\t\t\t");
break;
}
default: {
// types other than String and Numeric.
System.out.println("Type not supported.");
break;
}
}
}
}
}
/**
* The main executable method to test displayFromExcel method.
*
* @param args
*/
public static void main(String[] args) {
xssff poiExample = new xssff();
String xlsPath = "c://temp//data.xlsx";
poiExample.displayFromExcel(xlsPath);
}
}
好的,我發現了你的問題,你正在創建一本沒有床單的新書
XSSFWorkbook workBook = new XSSFWorkbook();
XSSFSheet sheet = workBook.getSheetAt(1); //error here, the workBook book has NO sheets!
您應該基於InputStream創建該書
XSSFWorkbook workBook = WorkbookFactory.create(new PushbackInputStream(inputStream));
XSSFSheet sheet = workBook.getSheetAt(1);
或者更簡單,只需傳遞文件名即可創建圖書:
XSSFWorkbook workBook = new XSSFWorkbook(xlsPath);
XSSFSheet sheet = workBook.getSheetAt(1);
嘗試這個:
// Create Workbook instance holding reference to .xlsx file
XSSFWorkbook workbook = new XSSFWorkbook();
XSSFSheet sheet = createSheet(workbook, "Sheet 1", false);
XSSFRow row1 = sheet.createRow(0);
那個功能是:
private static XSSFSheet createSheet(XSSFWorkbook wb, String prefix, boolean isHidden) {
XSSFSheet sheet = null;
int count = 0;
for (int i = 0; i < wb.getNumberOfSheets(); i++) {
String sName = wb.getSheetName(i);
if (sName.startsWith(prefix))
count++;
}
if (count > 0) {
sheet = wb.createSheet(prefix + count);
} else
sheet = wb.createSheet(prefix);
if (isHidden)
wb.setSheetHidden(wb.getNumberOfSheets() - 1, XSSFWorkbook.SHEET_STATE_VERY_HIDDEN);
return sheet;
}
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