[英]A len(list) gives TypeError: object of type 'NoneType' has no len()
[英]object of type 'NoneType' has no len(), but I'm pretty sure my object is a valid list
以下模塊對我來說一直失敗,告訴我'NoneType'類型的對象沒有len(),但是似乎傳遞的對象是列表,而不是'NoneType'類型的對象。 我在下面包括模塊和輸出。
def Purge_Polyploid_MisScores(dictOfLists):
#print "dict getting passed to Purge_Polyploid_MisScores function", dictOfLists
for x in dictOfLists.keys():
for y in range (0, len(dictOfLists[x])):
print "x", x, " and y", y
print dictOfLists[x][y]
#if not dictOfLists[x][y]:
#print "error at ",x,dictOfLists[str(int(x)-1)][0]
if len(dictOfLists[x][y])>3:
try:
dictOfLists[x][y]=dictOfLists[x][y].remove('**')
except:
for z in dictOfLists[x][y]:
if dictOfLists[x][y].count(z)>2:
print "removed ",z," at dictOfLists[",x,"][",y,"]", dictOfLists[x][y]
dictOfLists[x][y].remove(z)
#I think this produces an error: dictOfLists[x][y]=dictOfLists[x][y].remove(z)
print "now, it looks like", dictOfLists[x][y]
if len(dictOfLists[x][y])>3:
print "The Length is still greater than 3! at dictOfLists[",x,"][",y,"]", dictOfLists[x][y]
#print "the reason you have a polyploid is not a mis-score"
#print "dictOfLists[",x,"][",y,"]",dictOfLists[x][y]
print "Reached the end of the loop"
return dictOfLists
錯誤/錯誤之前的輸出:
x 449 and y 100
['Yellow submarine', '273', '273']
Reached the end of the loop
x 449 and y 101
['Heartland', '250', '250', '250']
removed 250 at dictOfLists[ 449 ][ 101 ] ['Heartland', '250', '250', '250']
now, it looks like ['Heartland', '250', '250']
Reached the end of the loop
x 449 and y 102
['Julia', '116', '119', '**']
Traceback (most recent call last):
File "fast_run.py", line 11, in <module>
sample_names_list_e1_keys_as_numbers_e2=transpose.combine_allele_report_pipeline_dict(pipeline_directory, keeplist_address, rejected_samples_address)
File "/Users/markfisher/transpose.py", line 887, in combine_allele_report_pipeline_dict
samples=Purge_Polyploid_MisScores(samples)
File "/Users/markfisher/transpose.py", line 1332, in Purge_Polyploid_MisScores
if len(dictOfLists[x][y])>3:
TypeError: object of type 'NoneType' has no len()
換句話說,如果len(['Julia', '116', '119', '**'])>3
, ['Julia', '116', '119', '**']
似乎失敗了len(['Julia', '116', '119', '**'])>3
,我不知道為什么。
我希望我已經為你們提供了足夠的裝備,讓我看到我的錯誤! 謝謝!
問題是這樣的: dictOfLists[x][y]=dictOfLists[x][y].remove('**')
。 列表的remove
方法將就地刪除元素,使原始列表發生變異,並返回None,因此您將列表設置為None。 相反,只需執行dictOfLists[x][y].remove('**')
。
@BrenBarn得到了正確的答案,我知道這應該是評論,而不是答案; 但我無法在注釋中張貼代碼。
如果在循環中您有9次dictOfLists[x][y]
,則結構上有問題。
items()
獲取鍵和值,而不只是鍵,然后查找值 enumerate
獲取列表中的索引和值,而不是遍歷整個range(len(
更像是:
def Purge_Polyploid_MisScores(dictOfLists):
for key,lst in dictOfLists.items():
for i,val in enumerate(lst):
print "key: %s index: %i val: %s"%(key,i,val)
if len(val)>3:
val.remove('**')
抱歉,如果您有改寫的罪行,但是您考慮過要發布測試代碼(+1),所以我想給您帶來建設性的(希望)回報
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