[英]Simple sql multi-table query
我在我的網站上編寫了一個聊天室,但我對php很新。 我希望用戶能夠與在游戲的相同團隊中玩的用戶聊天(知道用戶可以一起參與不同的團隊)以及在同一區域工作的用戶。
假設有三個表:帳戶用戶的表,區域的能力,游戲的表格
我有一個函數返回我的查詢
function myfunction($userid){
$games_user=mysql_query('select theme from games where games.userid="'.$userid.'"');
$games_theme = mysql_fetch_array($games_user);
$sql = ("select userid, username, area.userid
from account
left join area
on account.userid = area.userid
left join games
on account.userid = games.userid
where account.userid <> '".mysql_real_escape_string($userid)."' and '".(in_array(games.theme,$games_theme))."' and area.userid=1
);
return $sql;
}
重新格式化:
$sql = "
SELECT userid, username, area.userid
FROM account
LEFT JOIN area ON account.userid = area.userid
LEFT JOIN games ON account.userid = games.userid
WHERE account.userid <> '".mysql_real_escape_string($userid)."'
AND '".(in_array(games.theme,$games_theme))."'
AND area.userid = 1
";
但它確實不起作用,我認為我有語法問題。 我真的不明白in_array是如何編入索引的,而且我不知道如何以更簡單的方式進行查詢
有人可以幫忙嗎?
我還不完全確定你在做什么,但我認為這就是你想要的; 您可以在一個查詢中執行此操作:
<?php
function myfunction($userid){
$id = mysql_real_escape_string($userid);
$sql = "SELECT userid, username, area.userid
FROM account
LEFT JOIN area
ON account.userid = area.userid
LEFT JOIN games
ON account.userid = games.userid
WHERE account.userid<>'$id' AND area.userid=1
AND games.theme IN (SELECT theme FROM games WHERE games.userid='$id')
";
return $sql;
}
?>
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