[英]Strip PHP tags preg_replace
我想從外部文本中刪除所有php標簽,以便可以安全地將其包含在php中。
這是示例輸入:
<?
?>
<html>
<?php ?>
<?= ?>
</html>
<?
或任何其他可能性
並輸出:
<html>
</html>
最后一個php open標簽可能沒有結束標簽!
我認為沒有一種很好的方法可以精確地完成您想要的操作,但是如果可以在輸出中發送PHP標記(未解析),則可以使用:
<?php echo file_get_contents('input.html'); ?>
否則,請看一下token_get_all方法:
http://www.php.net/manual/en/function.token-get-all.php
您可以遍歷所有結果,僅返回T_INLINE_HTML類型的結果:
$toks = token_get_all( file_get_contents( 'input.html' ) );
foreach( $toks as $tok ) {
if( $tok[0] == T_INLINE_HTML ) {
print $tok[1];
}
}
正確的方法是不包含它,而是使用file_get_contents()
其作為字符串加載。 這將保留PHP標記而不執行它們。 但是,以下正則表達式將完全滿足您的要求:
#<\?.*?(\?>|$)#s
這是該字符串代表的細分:
# A delimiter marking the beginning and end of the expression - nearly anything will do (preferably something not in the regex itself) <\? Find the text "<?", which is the beginning of a PHP tag. Note that a backslash before the question mark is needed because question marks normally do something special in regular expressions. .*? Include as much text as necessary (".*"), but as little as possible ("?"). (\?>|$) Stop at an ending PHP tag ("?>"), OR the end of the text ("$"). This doesn't necessarily have to stop at the first one, but since the previous part is "as little as possible", it will. # The same delimiter, marking the end of the expression s A special flag, indicating that the pattern can span multiple lines. Without it, the regex would expect to find the entire PHP tag (beginning and end) on a single line.
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