如何使用php從MySQL查詢中獲取索引值？

Question

嗨，我正在從mysql數據庫中獲取數據，我想獲取表中各列的索引

<?php 
//connects to database 
$con = mysql_connect("locahost","root","");
if (!$con) 
{ 
die('Could not connect: ' . mysql_error()); 
} 

mysql_select_db("appulentoweb", $con); 

//retrieve data from database 
$result = mysql_query("SELECT * FROM questions"); 
?> 

我想獲取表中各列的索引，然后將在屏幕上顯示該數據。

在表中我有2列，即qno和titile，我想在輸出頁面中顯示標題

提前致謝...

Answer 1

請嘗試這個。

   <?php  
        //connects to database  
        $con = mysql_connect("locahost","root",""); 
        if (!$con)  
        {  
        die('Could not connect: ' . mysql_error());  
        }  

        mysql_select_db("appulentoweb", $con);  

        //retrieve data from database  
        $result = mysql_query("SELECT * FROM questions"); ?>

        <table>
           <tr>
              <th> Question no</th>
              <th> Question </th>
           </tr>
        <?php 
        while($row=mysql_fetch_array($result))
        {
         ?>
         <tr>
            <td><?php echo $row['qno'];?></td>
            <td><?php echo $row['question'];?></td></tr>
  <?php } ?>
    </table>

希望對您有所幫助。

如果您有問題，請告訴我...

Answer 2

嘗試這個;

 <?php  
//connects to database  
$con = mysql_connect("locahost","root",""); 
if (!$con)  
{  
die('Could not connect: ' . mysql_error());  
}  

mysql_select_db("appulentoweb", $con);  

//retrieve data from database  
$result = mysql_query("SELECT * FROM questions");  
    $rows = mysql_fetch_array($result, MYSQL_ASSOC);
    echo $rows['qno'];
    echo $rows['title'];

要么

$rows = mysql_fetch_array($result, MYSQL_NUM);
        echo $rows[0];
        echo $rows[1];

?>

Answer 3

您可以使用函數mysql_fetch_array返回索引數組和關聯數組。