SQL選擇在哪里使用查詢字符串

Question

如果我有這兩個復雜的查詢字符串

 ALM_frmTopAlarmHistoryReport.aspx?strAlarmConnection=AlarmSystem

和

 http://1.1.4.1/xyz/ALM_frmAlarmHistoryReport.aspx?ViewPDF=
 1&dtmStartDate={0}&dtmEndDate={1}& + '&lngAlarmGroup=' + 
 $('#ddlAlarmGroup').val() + '&lngProcessor=' + $('#ddlProcessor').val() + 
 '&intCategory=' + $('#ddlCategory').val()

我怎樣才能排除我嘗試過的select WHERE LIKE類似條件

 SELECT * FROM [tablename] WHERE string1 LIKE '%string2%' 

我得到了以下錯誤

   Msg 103, Level 15, State 4, Line 1
   The identifier that starts with'%string2 ' is too long. Maximum length is 128.

任何幫助將非常受歡迎，謝謝

Answer 1

使用locate或instr代替：

select *
from tablename
where instr(string2, string1)  > 0