使用JOIN和GROUP_CONCAT的MySQL

Question

努力使此查詢正常工作：

$query_search = "SELECT questionnaires_index.id, questionnaires_index.ea_num, questionnaires_index.address, questionnaires_index.status, questionnaires_index.json_stored users.username FROM questionnaires_index INNER JOIN users ON questionnaires_index.interviewer_id = users.id WHERE questionnaires_index.interviewer_id IN (SELECT GROUP_CONCAT(id) FROM users WHERE supervisor = (SELECT id FROM users WHERE username = '".$username."'))";

收到此錯誤：

查詢錯誤：。 您的SQL語法有誤； 檢查與您的MySQL服務器版本對應的手冊以獲取正確的語法，以在第1行的'.username FROM surveys_index INNER JOIN users ON users.id = survey'附近使用

該查詢一直有效，直到我使用JOIN語句將users.username添加到結果集中。 請幫忙。

Answer 1

您錯過了一個逗號

$ query_search =“ SELECT問卷調查表_index.id，問卷調查表_index.ea_num，問卷調查表_index.address，問卷調查表_index.status，問卷調查表_index.json_stored，users.username FROM問卷調查表_INNER JOIN的用戶在問卷調查表中_query.index.interviewer_id = users.id WHERE問卷調查表_index.interviewer_id IN（選擇GROUP_CONCAT id）FROM Users WHERE Supervisor =（從用戶WHERE username ='“。$ username。”''））的用戶選擇ID；

Answer 2

您似乎忘記了在surveys_index.json_stored和users.username之間使用逗號。

$query_search = "SELECT questionnaires_index.id, questionnaires_index.ea_num, questionnaires_index.address, questionnaires_index.status, questionnaires_index.json_stored ,users.username FROM questionnaires_index INNER JOIN users ON questionnaires_index.interviewer_id = users.id WHERE questionnaires_index.interviewer_id IN (SELECT GROUP_CONCAT(id) FROM users WHERE supervisor = (SELECT id FROM users WHERE username = '".$username."'))