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[英]Detecting which selected item (in a ListView multicolumn) spawned the ContextMenu (Android)
[英]Detecting which selected item (in a ListView) spawned the ContextMenu
我在listView的每個項目中都有兩個Edit Text。 當用戶長按listView中的任何項目時,我將顯示一個contextMenu並提供兩個選項,現在如何編輯和刪除,我如何知道用戶長按listView中的哪個項目以打開上下文菜單。
XML of each item of ListView
<?xml version="1.0" encoding="utf-8"?>
<TextView android:id="@+id/templateId"
android:layout_width="wrap_content"
android:layout_height="wrap_content"/>
<TextView android:id="@+id/templateTextId"
android:layout_width="wrap_content"
android:layout_height="wrap_content"/>
XML for context menu
<?xml version="1.0" encoding="utf-8"?>
<menu
xmlns:android="http://schemas.android.com/apk/res/android">
<item android:id="@+id/editTemplate"
android:title="Edit" />
<item android:id="@+id/saveTemplate"
android:title="Save" />
<item android:id="@+id/deleTemplate"
android:title="Delete" />
Code
@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo)
{
super.onCreateContextMenu(menu, v, menuInfo);
menu.setHeaderTitle("Select The Action");
menu.add(0, v.getId(), 0, "Edit");
menu.add(0, v.getId(), 0, "Delete");
TextView tv=(TextView)v.findViewById(R.id.templateId);
selectedId=tv.getText().toString();
TextView tvMessage=(TextView)v.findViewById(R.id.templateTextId);
selectedTemplate=tvMessage.getText().toString();
//Toast.makeText(getApplicationContext(), "Item In List View Clicked ",Toast.LENGTH_SHORT).show();
}
@Override
public boolean onContextItemSelected(MenuItem item) {
if(item.getTitle()=="Edit")
{
// Toast.makeText(ShowTemplates.this, "Edit Clicked",Toast.LENGTH_SHORT).show();
Context mContext = getApplicationContext();
Dialog dialog = new Dialog(ShowTemplates.this);
dialog.setContentView(R.layout.custome_dialog_edit_template);
dialog.setTitle("Edit Template");
txtMsgTemplate = (EditText) dialog.findViewById(R.id.editTextTemplateCustomDialog);
txtMsgTemplate.setText(selectedTemplate);
Button btnSave=(Button)dialog.findViewById(R.id.btnSaveEditedTemplate);
dialog.show();
}
我試圖找到它,我得到了關注
@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo) {
super.onCreateContextMenu(menu, v, menuInfo);
// Get the info on which item was selected
AdapterContextMenuInfo info = (AdapterContextMenuInfo) menuInfo;
// Get the Adapter behind your ListView (this assumes you're using
// a ListActivity; if you're not, you'll have to store the Adapter yourself
// in some way that can be accessed here.)
Adapter adapter = getListAdapter();
// Retrieve the item that was clicked on
Object item = adapter.getItem(info.position);
}
但是我不知道如何使用這個Item對象。 還有其他方法可以做到這一點。 謝謝
ListViews具有一個名為getSelectedItemPosition
的函數,該函數返回一個帶有項目在適配器中位置的int。 我很確定您可以使用它。 如果在onCreateContextMenu
中為null,則嘗試在onLongClick listener
獲取對其的引用。
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