我的Android應用多次檢測到同一藍牙設備

Question

我正在使用Android開發人員網站上的代碼來檢測范圍內的藍牙設備，並將它們添加到ArrayAdapter中。 問題是，每個設備被添加到ArrayAdapter的次數為5-6次。 現在，我只是使用此處的代碼： http : //developer.android.com/guide/topics/connectivity/bluetooth.html#DiscoveringDevices

這是我所擁有的：

mBluetoothAdapter = BluetoothAdapter.getDefaultAdapter();      
mBluetoothAdapter.startDiscovery();

final BroadcastReceiver mReceiver = new BroadcastReceiver() {
    public void onReceive(Context context, Intent intent) {
        String action = intent.getAction();

        // When discovery finds a device
        if (BluetoothDevice.ACTION_FOUND.equals(action)) {
            // Get the BluetoothDevice object from the Intent
            BluetoothDevice device = intent.getParcelableExtra(BluetoothDevice.EXTRA_DEVICE);

            // Add the name and address to an array adapter to show in a ListView
            mArrayAdapter.add(device.getName() + "\n" + device.getAddress());
        }
    }
};

知道是什么原因造成的嗎？ 我該怎么做才能將設備僅添加到ArrayAdapter一次，而不是5次？

Answer 1

我不確定這是錯誤還是什么，但是我在某些設備上也經歷過。 要解決此問題，請在一次檢查中將找到的設備僅添加到List一次。 見下文：

private List<BluetoothDevice> tmpBtChecker = new ArrayList<BluetoothDevice>();

    final BroadcastReceiver mReceiver = new BroadcastReceiver() {
        public void onReceive(Context context, Intent intent) {
            String action = intent.getAction();

            // When discovery starts    
            if(BluetoothAdapter.ACTION_DISCOVERY_STARTED.equals(action)){
                //clearing any existing list data
                tmpBtChecker.clear();
            }

            // When discovery finds a device
            if (BluetoothDevice.ACTION_FOUND.equals(action)) {
                // Get the BluetoothDevice object from the Intent
                BluetoothDevice device = 
                    intent.getParcelableExtra(BluetoothDevice.EXTRA_DEVICE);

                // Add the name and address to an array adapter
                if(!tmpBtChecker.contains(device)){
                   tmpBtChecker.add(device);
                   mArrayAdapter.add(device.getName()+"\n"+device.getAddress());
                }
            }
        }
    };